<span>Chicken have 2 legs. Rabbits have 4 legs. Let the number of chicken be x and the number of rabbits be y. Then we have the following equations: x + y = 72 (the total number of animals in the cage) and 2x + 4y = 200 (the total number of legs in the cage). In the first equation we express x relative to y and get that x = 72 - y. Then we replace it in the second equation and get 2*(72 - y) + 4y = 200 <=> 144 + 2y = 200 <=> y = 56/2 <=> y = 28. And since x = 72 - y we get that x = 44. So in total we have 44 chicken and 28 rabbits.</span>
F(x) = |x + 2| - 3
0 = |x + 2| - 3
0 = x + 2 - 3
0 = x - 1
+ 1 + 1
1 = x
Domain: x > 1 and x < 1
Solution Set of the Domain: {x| 1 > x > 1} and {x|x 1 < x < 1} or (1, 1)
f(x) = |x + 2| - 3
f(x) = |0 + 2| - 3
f(x) = |2| - 3
f(x) = 2 - 3
f(x) = -1
Range: x ≤ 3
Solution Set of the Range: {x|x ≤ 3} or (-∞, 3]
Answer:
C
Step-by-step explanation:
Using Pythagoras' identity in right triangle BPO
with PB = 4 ( half of AB ) and OB = 5 ( radius of circle )
OP² + 4² = 5²
OP² + 16 = 25 ( subtract 16 from both sides )
OP² = 9 ( take the square root of both sides )
OP = 
= 3
48 ÷ 12 + 7 x 2 ÷ 2 - 1
4+7x2÷2-1
4+14÷2-1.
4+7-1
11-1
10
2x^3-4x^2+2-x^3+2x^2+2x-4
x^3-2x^2+2x-2
