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2 years ago

On a plan with a scale of 1:50 a wardrobe shows up as 3cm long.

Mathematics

1 answer:

andreev551 [17]2 years ago

7 0

Answer:

Assuming the scale is 1cm:50m then the answer is 150m

Step-by-step explanation:

1 cm is directly proportional to 50m so 3cm would be multiplied by 50m to find the answer. And 3 × 50 = 150

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Enforce is to impose as fued is to

jenyasd209 [6]

The reasonable answer should be Dispute.

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3 years ago

Which expression is equivalent to m^2-13m-30?

sergiy2304 [10]

Answer: First option

Step-by-step explanation:

You have the quadratic equation given in the problem:

$m^2-13m-30$

To find an equivalent expression you cacn factorize. Find two numbers whose sum is -13 and whose product is -30.

These numbers would be -15 and 2.

Therfore, you obtain the following equivalent expression:

$(m-15)(m+2)$

If you don't want to apply the method above, you can use the quadratic formula:

$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$

Where:

$a=1\\b=-13\\c=-30$

When you susbstitute values you obtain that:

$x=15\\x=-2$

Then you can rewrite the equation as $(m-15)(m+2)$

7 0

2 years ago

Read 2 more answers

What are the critical points for the inequality 2x+5/x-2≥x-1/x-2?

Pachacha [2.7K]

1) When the denominator equals zero that is a critical point

=> x - 2 = 0 => x = 2.

So x = 2 is a critical point

2) Simplify the numerator to find an expresion of the king p(x) ≥ 0 or p(x) ≤ 0. Where p(x) equals zero you have other(s) critical point(s)

Multiply both terms:

[2x + 5] / [ x - 2] = [x - 1] / [x - 2]

for x ≠ 2 => 2x + 5 = x - 1

=> 2x - x = - 1 - 5

=> x = - 6

Then, the two critical points are x = 2 and x = - 6.

Answer: option B.

3 0

3 years ago

Read 2 more answers

Plz help me<br> 20 points

wel

Answer:

Step-by-step explanation:

Hope this helps! Pls give brainliest!

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2 years ago

Read 2 more answers

Figure this out please Asap.

weeeeeb [17]

If the polygons are similar then the sides are in proportion.

$\dfrac{32}{24}=\dfrac{32:8}{24:8}=\dfrac{4}{3}$

Therefore we have the equations:

$\dfrac{x-1}{6}=\dfrac{4}{3}\qquad\text{cross multiply}\\\\3(x-1)=(4)(6)\\\\3x-3=24\qquad\text{add 3 to both sides}\\\\3x=27\qquad\text{divide both sides by 3}\\\\\boxed{x=9}$

$\dfrac{y+1}{21}=\dfrac{4}{3}\qquad\text{cross multiply}\\\\3(y+1)=(21)(4)\\\\3y+3=84\qquad\text{subtract 3 from both sides}\\\\3y=81\qquad\text{divide both sides by 3}\\\\\boxed{y=27}$

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3 years ago