Answer:in first part of equation add 10x and 3x (like terms)
13x-4.5=12x-1.1
move all terms containing x to left side of equation
13x-4.5-12x= -1.1
x-4.5= -1.1
Subtract 4.5 from both sides
x=3.4
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
the angle in a semicircle = 90° , that is the 3rd angle in the triangle.
the sum of the 3 angles in a triangle = 180° , then
p + 90° + 42° = 180°
p + 132° = 180° ( subtract 142° from both sides )
p = 48°
-a²-3b³+c²+2b³-c²
= -(3)² - (3×2)³ + (-3)² + (2 × 2)³ - ( -3)²
= 9 - 24 + 9 + 16 - 9
= 1
answer is 1.
Answer:
The value of k that makes the relationship shown in the table below proportional is 
Step-by-step explanation:
The relation is proportional if 
Putting values of x and y to find k.
For x =2 and y =1 k is: 
For x =4 and y =2 k is: 
For x =6 and y = 3 k is: 
For x = 8 and y = 4 k is: 
For x =10 and y = 5 k is: 
So, The value of k that makes the relationship shown in the table below proportional is 