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3 years ago

From a class of twenty students, how many different ways can the 1 , 2 , and 3rd students be chosen?

Mathematics

1 answer:

lana [24]3 years ago

7 0

Answer:

They can be chosen in 6,840 different ways

Step-by-step explanation:

In this question, we are tasked with calculating the number of ways in which the 1st, 2nd and 3rd students can be chosen.

For the first position, we have 20 people vying for the position and we are to select only one for the position.

The number of ways this is achievable is 20C1 ways = 20 ways

For the second position, we are left with 19 students vying for the position and we are to select only one for the position. The number of ways this is possible is 19C1 ways = 19 ways

For the third position, we are left with 18 students vying for the position. The number of ways this is possible is 18C1 ways = 18 ways

Thus, the total number of ways this cane be done is; 20 ×19 ×18 = 6,840 ways

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Answer:

$\frac{-1}{4}$ and $\frac{-5}{8}$ are the locations higher than $\frac{-3}{4}$ foot

Step-by-step explanation:

We are given that Meg found one treasure at $\frac{-3}{4}$ foot

We are supposed to find Which of these location are higher than $\frac{-3}{4}$ foot?

i) $-\frac{7}{8}$

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ii) $-\frac{1}{4}$

So, $-\frac{1}{4}>\frac{-3}{4}$

So, this location is higher than $\frac{-3}{4}$ foot

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v) $\frac{-5}{8}$

So, this location is higher than $\frac{-3}{4}$ foot

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3 years ago

A system of linear equations has been graphed in the diagram. determine a reasonable solution for the system of equations.

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Answer:

(1,-1)

Step-by-step explanation:

The solution to a system of equation means the x and y values if we were to solve both equations (of lines) simultaneously.

That is also known as the intersecting points.

The top-right part is known as the 1st Quadrant in a coordinate system.

Top-left is 2nd Quadrant.

Bottom left is 3rd Quadrant.

Bottom right is 4th Quadrant.

The values of x and y (positive or negative) of each quadrant is shown below:

Quadrant 1: x +ve, y +ve
Quadrant 2: x -ve, y +ve
Quadrant 3: x -ve, y -ve
Quadrant 4: x +ve, y -ve

The intersection point (solution) of the 2 lines shown is in the 4th quadrant, which has x values positive and y values negative.

From the answer choices, we see that 3rd answer choice goes with this -- (1,-1), so this is the correct choice.

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Answer:

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Step-by-step explanation:

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