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3 years ago

Ben used 325 centimeters of ribbon to trim banners he made. How many meters of ribbon did he use?

Mathematics

2 answers:

Artyom0805 [142]3 years ago

4 0

Answer:

3.25

Step-by-step explanation:

AleksandrR [38]3 years ago

3 0

3 1/4
1meter =100 cm

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To solve the inequality m/-7<(or equal to) 14 , what should be done to both sides?

Marizza181 [45]

Answer:

$\large\boxed{m\geq-98}$

Step-by-step explanation:

$\dfrac{m}{-7}\leq14\\\\-\dfrac{m}{7}\leq14\qquad\text{change the signs}\\\\\dfrac{m}{7}\geq-14\qquad\text{multiply both sides by 7}\\\\7\!\!\!\!\diagup^1\cdot\dfrac{m}{7\!\!\!\!\diagup_1}\geq(7)(-14)\\\\m\geq-98$

5 0

3 years ago

Read 2 more answers

Fifteen more than z times 6 is 11 less than y times 2

nata0808 [166]

<h3>Given:</h3>

Fifteen more than z times 6 is 11 less than y times 2

<h3>Solution:</h3>

Fifteen more than z times 6 = 6z + 15

11 less than y times 2 = 2y - 11

<h2>Answer:</h2>

6z + 15 = 2y - 11

7 0

3 years ago

18(5−3w) =<br> can someone help me pls

nika2105 [10]

Answer:

90-54w

Step-by-step explanation:

use the distributive property

3 0

3 years ago

Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.

tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: $\frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3}$ square units

(22)

Similar to (21)

Area = $216\sqrt{3}$ square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

$altitude=\frac{\sqrt{3}}{2}*side$