The set of lines from this play that shows that Olivia returned the ring because she wanted Cesario to visit her again is
- Where Cesario says: She loves me, sure: the cunning of her passion invites me in this churlish messenger and
- The line where Malvolio talked about the reason why the ring was being returned.
In this line, Malvolio accuses Viola who disguised as Cesario of throwing the ring at Olivia peevishly.
According to him, the ring had to also be returned in such a manner. Returning the ring in such a manner was done to have Cesario go back to offer the ring back to olivia.
<h3>Summary of the play twelfth night.</h3>
This play is a comedy that is based on love, mistaken identity and lots of Jokes. It was written by the playwright Shakespeare.
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D.
If you are also asking this from a personal standpoint, my advice is that the dual enrollment courses are much easier. However, this may not be the best option depending on which college it is based through (Dual credit is NOT universal, and there are some colleges, especially the ones that are harder to get into, that will not accept transfer credit from many colleges.) My advice would be, if you don't know where you are going to college yet, to take the AP and study a lot for that test. Or, if you know where you are going, to take advantage of CLEP tests, which are easier and strictly pass/fail subject tests. Most colleges would have the AP/Transfer Credit/CLEP requirements on their websites if you do a little digging.
I think that the answer is D
Based on the calculations, the molar solubility of AgCl in 0. 500 M of NH₃ is equal to 2.77 × 10⁻² M.
<u>Given the following data:</u>
- Ksp of mg(oh)₂ = 1.8 × 10⁻¹⁰
- Concentration of NH₃ = 0.500
- Kf of ag(nh₃)₂⁺ = 1.7 × 10⁷
<h3>How to determine the molar solubility.</h3>
First of al, we would write the properly balanced chemical equation for this chemical reaction:
Ksp = 1.8 × 10⁻¹⁰
Kf = 1. 7 × 10⁷
K = Ksp × Kf
K = 1. 80 × 10⁻¹⁰ × 1.7 × 10⁷
K = 3.06 × 10⁻³
Mathematically, the Ksp for the above chemical reaction is given by:
x = 2.77 × 10⁻² M.
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There are different kinds of theory. The chemical equation that does not correspond to a standard molar enthalpy of formation is c. N₂(g) + O₂(g) ⇒ 2 NO(g).
<h3>What is standard enthalpy of formation ?</h3>
The standard enthalpy of formation of any element is known to often occur in the standard state that is zero of that element.
For example, even though oxygen can be found as ozone (O3), O2 is the known to be the most stable form.
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