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Kazeer [188]
2 years ago
10

Select whether the pair of lines is parallel, perpendicular, or neither. x=−2, y=10

Mathematics
1 answer:
Mila [183]2 years ago
3 0

Answer:

perpendicular

Step-by-step explanation:

x = -2    is a vertical line at   x   =  -2

y is a horizontal line          the two lines are perpindicular

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What is 86 14/24 + 7 13/24
Lera25 [3.4K]

Answer:

94 3/24

Step-by-step explanation:

86 14/24 + 7 13/24 = 86 + 7 + 14/24 + 13/24

                                = 93 + (14+13)/24

                   = 93 + 27/24  

                        {here 27/24 is improper fraction. so convert to mixed fraction }

                                 = 93 + 1  3/24

                                  = 94 3/24

3 0
3 years ago
Hey need help with some homework my teacher did not explain this very well so could you help me answer it and explain how iis do
Diano4ka-milaya [45]
<span>y in (-oo:+oo)

(3*y+6)/11 = -9 // + 9

(3*y+6)/11+9 = 0

(3*y+6)/11+(9*11)/11 = 0

3*y+9*11+6 = 0

3*y+105 = 0

(3*y+105)/11 = 0

(3*y+105)/11 = 0 // * 11

3*y+105 = 0

3*y+105 = 0 // - 105

3*y = -105 // : 3

y = -105/3

y = -35

y = -35</span>
7 0
3 years ago
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6a+5a= -11 sole each equation
iren [92.7K]

Answer:

789

Step-by-step explanation:

5 0
4 years ago
The 8th term of a GP is -7/32 find its common ratio if its first term is 28
Ugo [173]
<h2>Common ratio = -1/2</h2>

Step-by-step explanation:

       \text{8}^{th} term of a Geometric progression is given as \dfrac{-7}{32}. The first term is given as 28.

       Any general Geometric progression can be represented using the series a,ar,ar^{2},ar^{3},ar^{4}...\text{ }ar^{n-1}.

The first term in such a GP is given by a, common ratio by r, and the n^{th} term is given by ar^{n-1}.

       In the given GP, a=28;t_{8}=ar^{7}=\dfrac{-7}{32}\\\\28r^{7}=\dfrac{-7}{32}\\\\r^{7}=\dfrac{-1}{128}\\\\r=\dfrac{-1}{2}

∴ Common ratio is \dfrac{-1}{2}.

5 0
3 years ago
What is 4x4= with this problem
barxatty [35]
Hewo

Answer:

16

Explanation:

4*4 is 16
5 0
3 years ago
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