Answer: The required three consecutive odd integers are 7, 9 , 11.
Step-by-step explanation:
Let x , x+2 , x+4 be the three consecutive odd integers.
As per given ,
10(x) = 59+x+4
⇒10x= 59+x+4
⇒ 9x= 63
⇒ x= 7 [ divide both sides by 7]
Hence, the required three consecutive odd integers are 7, 9 , 11.
The commission of telemarketer will be $75.
Step-by-step explanation:
Given,
Worth of subscription sales = $375
Commission rate = 20%
Amount of commission = 20% of worth of subscription sales
Amount of commission = 
Amount of commission = 
Amount of commission = $75
The commission of telemarketer will be $75.
Keywords: percentage, multiplication
Learn more about percentages at:
#LearnwithBrainly
Answer:
The answer is 8 quarters, 16 nickles, and 32 dimes
Step-by-step explanation:
- First, the equation would be (2/4d) x 5 +d x 10 +1/4d x 25= 600 (Don't put 6.00, that's dollars. We put 6 dollars into cents to make it easier.)
- Then we slowly start to solve: 10/4d + 10d + 25/4d = 600
- 10d+40d+25d/4 = 600 (Put all of that over 4, not first 25d)
- 75d= 600 x 4
- d=600 x 4/75 (same here put everything over 75)
- d=32
- So then n= 2 x 32/4 = 16
- Then n would be equal to : 1/4d= 1/4 x 32 = 8
- So your answer would be 8 quarters, 16 nickles, and 32 dimes.
Hope this helped :)
Forts then you take the 1-6 to get the money back and get your credit
Answer:
-1
Step-by-step explanation:
We need to simplify the given expression . The given expression is ,
Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,
Using this property , we have ,
This can be written as ,
Simplifying using ( a+b)(a-b) = a² - b² ,
Subtracting the numbers inside the brackets ,
Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .
Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,
<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>.</u>