What is the product of 6 and 7 square root 128 in simplest radical form

Mathematics

1 answer:

Novay_Z [31]2 years ago

7 0

Answer:

Step-by-step explanation:

<h3>For a radical to be in the simplest form, it </h3><h2>means it has been simplified in such away that there are no more square root, cube </h2><h2>roots, 4th root, etc left to be found.</h2>

product of 6 and 7= 6×7= 42

product of 6 and 7 square root 128= 42✓128

42✓128= 42✓64×2= 42×8✓2

42×8√2 = 336√2

therefore, the product of 6 and 7 square root 128 in simplest radical form is 336✓2

You might be interested in

8=−2/5c<br><br> Help me <br><br> I’m single ready to mingle

vitfil [10]

Answer:

-20

Step-by-step explanation:

First, you divide both sides by -2/5, which would get you c = 8 * -5/2 (Because when you divide, you multiply by the reciprocal). 8 * -5/2 is equal to -20. The answer is -20.

4 0

3 years ago

Which shows a reflection of the triangle?

lora16 [44]

C, or the last photo, shows a reflection.

4 0

3 years ago

Read 2 more answers

HELP QUICK.

lakkis [162]

Pretty sure it’s C That one makes the most sense to me please let me know if you get it right

5 0