kadeem has 58m of fencing to build a four-sided fence around a rectangular plot of land. the area of the land is 204 square mete

Question

1 year ago

7

rs. solve the dimensions of the field. (length and width)

2 answers:

tangare [24] · Answer 1 · 2023-04-07T07:39:51+03:00

5 0

I’m not quite sure what you mean so do this equation

64837//294738383&38373736

tankabanditka [31] · Answer 2 · 2023-04-07T05:15:20+03:00

The dimensions of the rectangular plot of the land is 17 × 12 square units.

<h3>What is perimeter?</h3>

The perimeter of a shape is the distance around the shape. It is the total length of the shape's sides.

<h3>What is the formula for the perimeter of rectangle?</h3>

Perimeter of rectangle = 2( length + width)

The area can be defined as the space occupied by a flat shape or the surface of an object.

<h3>What is formula for the area of rectangle?</h3>

Area of rectangle = length × width

According to the given question.

Let the length and width of the rectangular plot be x and y respectively.

Kadeem has 58m of fencing.

⇒ Perimeter of the rectangular plot of land = 58m

⇒ 2(length + width) = 58

⇒ x + y = 29...(i)

Also, area of plot land = 204 square units.

⇒ x × y = 204

⇒ x × (29 - x) = 204

⇒ $29x -x^{2} = 204$

⇒ $x^{2} -29x + 204=0$

⇒ $x^{2} -12x -17x +204=0$

⇒ $x(x-12)-17(x -12)=0$

⇒ $(x -12)(x -17) = 0$

⇒ x = 12 or x = 17

When, $x = 12$

$y = 29-12 = 17m$

And when, $x = 17$

$y = 29 - 17 = 12m$

Hence, the dimensions of the rectangular plot of the land is 17 × 12 square units.

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