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mezya [45]
3 years ago
15

The sum of 5 consecutive even numbers is 200 what is the fifth term in the sequence

Mathematics
1 answer:
Alex73 [517]3 years ago
5 0
Try this option:
if to write the given sequence as n;n+2;n+4;n+6;n+8, then it is possible to write its sum:
n+n+2+n+4+n+6+n+8=200.
5n=180; n=36.
n=36 it means that the 1st number is 36. The 5th number is n+8=36+8=44.
all the even numbers are: 36;38;40;42;44.

answer: 44.
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inessss [21]
Fh. = 40h + 120,  fh. = $200

200 = 40h + 120
200 - 120 = 40h
80 = 40h
 80/40  = h
  2 = h

h = 2 hours.
7 0
3 years ago
Determine the function which corresponds to the given graph <br> the asymptote is x= -1
MissTica

Answer:

Can't answer

Step-by-step explanation:

6 0
3 years ago
Helppppppppppppppppp
weqwewe [10]

Answer:

16.

Step-by-step explanation:

What does 75% Off mean? It means 75% of the price is subtracted. So find 75% of 64.

Here is our equation: 75/100 x 64 = 48.

So 48 dollars is going to be subtracted from 64, which gives us 64-48=16.

So the price of the wedding cake during the sale is 16.

3 0
3 years ago
If sinA+cosecA=3 find the value of sin2A+cosec2A​
Irina18 [472]

Answer:

\sin 2A + \csc 2A = 2.122

Step-by-step explanation:

Let f(A) = \sin A + \csc A, we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

\csc A = \frac{1}{\sin A} (1)

\sin^{2}A +\cos^{2}A = 1 (2)

Now we perform the operations: f(A) = 3

\sin A + \csc A = 3

\sin A + \frac{1}{\sin A} = 3

\sin ^{2}A + 1 = 3\cdot \sin A

\sin^{2}A -3\cdot \sin A +1 = 0 (3)

By the quadratic formula, we find the following solutions:

\sin A_{1} \approx 2.618 and \sin A_{2} \approx 0.382

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

\sin A \approx 0.382

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

A \approx 22.457^{\circ}

Then, the values of the cosine associated with that angle is:

\cos A \approx 0.924

Now, we have that f(A) = \sin 2A +\csc2A, we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

\sin 2A = 2\cdot \sin A\cdot \cos A (4)

\csc 2A = \frac{1}{\sin 2A} (5)

f(A) = \sin 2A + \csc 2A

f(A) = \sin 2A +  \frac{1}{\sin 2A}

f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}

f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}

If we know that \sin A \approx 0.382 and \cos A \approx 0.924, then the value of the function is:

f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}

f(A) = 2.122

8 0
3 years ago
-v + 5 + 6v = 1 + 5v + 3
Vedmedyk [2.9K]
Combine your like terms: 5v + 5 = 5v +4
subtract the 5v and 4 from each side:  0 = 1

because 0 \neq 1, there is no solution
8 0
3 years ago
Read 2 more answers
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