Answer:
y = 3, 4, or 5
Step-by-step explanation:
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<u>Step 1; Simplify the Double Inequality</u>
Let's first simplify this double inequality to make answering this problem a bit easier. This means getting the middle term to be just y, without any added constant or coefficients.
In this case, this is a fairly simple process, as all we have to do to get y by itself is just divide the <em>entire inequality</em> by 2. This means that we will also divide the 5 and 12 by 2. (Note that the signs stay the same because we are not dividing by a negative number.)
Doing so gives us the following double inequality: 2.5 < y < 6.
<u>Step 2: Identify the Integers in this Range</u>
Now that we have a simplified double inequality, all we need to do is find all of the integers in its range. (Recall that an integer is <u>any number that is not a fraction when fully simplified (ex. …-1, 0, 1...)</u>.)
In other words, we need to find all of the integers <em>in between</em> 2.5 and 6. Note that we don't include 6 because of the "<" sign, which indicates that the 2.5 and 6 are not included in the set. These numbers are 3, 4, and 5, making them your answer. Hope this helps!
The answers is 59/20 because when you calculate it it say 2.95
Equilateral triangle. because all sides are equal.
Answer:
<h3>a) 5 flowers</h3><h3>b) Trapezoid</h3>
Step-by-step explanation:
For one flower, the following shapes are used;
6 yellow hexagons, 2 red trapezoids and 9 green triangles
If we are given 30 yellow hexagons 50 red trapezoids and 60 green triangles, to get the number of flowers we can make, we will find the greatest common factor of 30, 50 and 60
30 = 6*5
50 = (2*5)+40
60 = (9*5)+15
We can see that 5 is common to all the factors. This means that we can make 5 flowers if they were changed to 30 yellow hexagons 50 red trapezoids and 60 green triangles.
Since there are 40 trapezoids left and 15 green triangles left, hence the shape that would have n as left over most is trapezoid (40 left over)
Answer: As x —> positive infinity, q(x) —> positive infinity, and as x —> negative infinity, q(x) —> positive infinity
Step-by-step explanation:
Khan Academy! Hope this helps
