Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
Answer:
a = 629
Step-by-step explanation:
a = w * L
w = 17
L = 2w + 3
a = (17) * (2w + 3)
a = (17) * (2(17) + 3)
a = 17 * (34 + 3)
a = 17 * (37)
a = 629
Answer:
The answer is option C.
<h3>-6, -5 2/5, -4 1/5</h3>
Step-by-step explanation:
The arithmetic sequence is given by

where n is the number of terms
<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>
n = 1
So we have



<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>
n = 4



<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>
n = 10



Hope this helps you
Answer:
w = 3
Step-by-step explanation:
19w - 1 = 11w + 23
19w - 11w = 23 + 1
8w = 24
w = 3