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Fantom [35]
2 years ago
6

A group of kids just finished trick-or-treating. The number of pieces of candy collected by each of the 5 kids is listed below.

Mathematics
1 answer:
AleksandrR [38]2 years ago
4 0
The standard deviation is about 3.81
To find standard deviation on calculator hit stat, 1, enter in each number, hit stat again, the hit the arrow to go to calc, then 1, and enter until it shows you the stats. The icon that says Sx is standard deviation for the data set you entered.
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Given the arithmetic sequence an= 2 - 3(n - 1), what is the domain for n?
wel
Generally we use n as a counter and begin it with 1:  the first term is obtained when n = 1.  Thus, n must be a positive integer, 1 or greater:  {1, 2, 3, ... }.

5 0
3 years ago
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The price of a shoes as reduced from 60 to 45. by what percentage was the price of the shoes reduced?
sweet-ann [11.9K]
45 is 75% of 60 but if you’re looking for the difference subtract 75 from 100, so 25%
8 0
3 years ago
I got an answer, but I only got one mark help
kaheart [24]

Answer:

The answer 323.4 is pound.

Step-by-step explanation:

First 25% and 8% together which is 33%.Then find out 33% of 980.33/100×980=323.4 pound.

So he saved 323.4 pound.

8 0
3 years ago
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An ice cream factory makes 100 quarts of ice cream in 5 hours how many quarts could be made in 36 hours
I am Lyosha [343]

Answer:

720 Quarts

Step-by-step explanation:

\frac{100}{5} = \frac{x}{36}

cross multiply

\frac{100}{5}*\frac{36}{36} = \frac{x}{36}*\frac{5}{5}\\\\\frac{3,600}{180}=\frac{5x}{180}

now that they are both divided by 180, we can eliminate it

3,600=5x\\\\\frac{3,600}{5}=\frac{5x}{5}\\\\720=x

7 0
3 years ago
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A new medical test provides a false positive result for hepatitis 2% of the time that is a perfectly healthy subject being teste
Oxana [17]
Given that X <span>be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.

The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02


Part A:

</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:

</span>P(X)={ ^nC_xp^x(1-p)^{n-x}} \\  \\ P(0)={ ^{30}C_0(0.02)^0(1-0.02)^{30-0}} \\  \\ =1(1)(0.98)^{30}=0.5455
<span>

Part B:

The mean of a binomial distribution is given by

</span>\mu=np \\  \\ =30(0.02) \\  \\ =0.6
<span>
The standard deviation is given by:

</span>\sigma=\sqrt{np(1-p)} \\ \\ =\sqrt{30(0.02)(1-0.02)} \\ \\ =\sqrt{30(0.02)(0.98)}=\sqrt{0.588} \\  \\ =0.7668
<span>

Part C:

This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>
5 0
3 years ago
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