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Savatey [412]
2 years ago
6

What is the median of the data?

Mathematics
2 answers:
Effectus [21]2 years ago
8 0

Answer:

The median is 3.

Step-by-step explanation:

Since, most of the values presented are 0-8 and median is the middle of any data set. It has to be 3.

LiRa [457]2 years ago
8 0
The median is 3
Have a nice day
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A sequence is defined recursively by f(1)=16 and f(n)= f(n-1)+2n. Find f(4)
lord [1]
Hi,

f(1)=16
f(2)=f(1)+2*2=16+4=20
f(3)=f(2)+2*3=20+6=26
f(4)=f(3)+2*4=26+8=34

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3 years ago
In quadrilateral DBCA, name the angles which are consecutive with angle D.
lisov135 [29]

Answer: The consecutive angles with angle D are B and A.

Explanation:

It is given that DBCA is a quadrilateral. Since it is a quadrilateral it means the have 4 vertices and 4 angles D, B,C,A.

The angles are formed in the order of the figure name. If the quadrilateral name is DBCA, So the order of the angles are D,B,C,A. It means the angle immediate after D is B, the angle immediate after B is C, the angle immediate after C is A and the angle immediate after A is D.

If the quadrilateral name is DBCA it means the sides are DB, BC, CA and AD as shown in the figure.

Consecutive angles of D means the angle immediate before and after the angle D.

In the figure there are some types of quadrilateral and from the figure we can easily noticed that the consecutive angles with angle D are B and A.

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3 years ago
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$5,000 is invested in two different accounts yielding 3% and 3.5% interest. The interest earned on the two accounts is $155. Let
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Svetllana [295]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

Calculate discriminant :

\qquad \sf  \dashrightarrow \: 3 {x}^{2}  + 6x - 1

  • a = 3
  • b = 6
  • c = 1

\qquad \sf  \dashrightarrow \: discriminant =  {b}^{2}  - 4ac

\qquad \sf  \dashrightarrow \: d = (6) {}^{2}  - (4 \times 3 \times 1)

\qquad \sf  \dashrightarrow \: d = 36 - 12

\qquad \sf  \dashrightarrow \: d = 24

\qquad \sf  \dashrightarrow \:  \sqrt {d} = 2 \sqrt{6}

Now, let's calculate it's roots ( x - intercepts )

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - b  \pm \sqrt{d} }{2a}

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6\pm 2 \sqrt{6}  }{2 \times 3}

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6\pm 2 \sqrt{6}  }{6}

So, the intercepts are :

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6 -  2 \sqrt{6}  }{6}

and

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6  +  2 \sqrt{6}  }{6}

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1 year ago
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