Equation of a line using 2 points. first find the slope
m= (y2-y1)/(x2-x1)= (3-3)/(-4-6)= 0/-10 = 0
m=0
using y-y1=m(x-x1)
we get
y-3=0(x-6)
y-3=0
y=3 is the equation of the line
Answer:
(a, b) = (-8, -29)
Step-by-step explanation:
The two relations can be written as the equations ...
a - b = 21
5a -2b = 18
Subtracting 2 times the first equation from the second, we have ...
(5a -2b) -2(a -b) = (18) -2(21)
3a = -24 . . . . . simplify
a = -8 . . . . . . . divide by 3
Substituting into the first equation, we have ...
-8 -b = 21
-b = 29 . . . . . . add 8
b = -29 . . . . . . multiply by -1
The values of a and b are -8 and -29, respectively.
Answer:
y= -9
Step-by-step explanation:
y+6=-3
subtract 6 from both sides
y=-9
Answer:
Please find attached a drawing of the triangles ΔRST and EFG showing the angles
The angle on ΔEFG that would prove the triangles are similar is ∠F = 25°
Step-by-step explanation:
In order to prove that two triangles are similar, two known angles of each the triangles need to be shown to be equal
Given that triangle ∠R and ∠S of triangle ΔRST are 95° and 25°, respectively, and that ∠E of ΔEFG is given as 90°, then the corresponding angle on ΔEFG to angle ∠S = 25° which is ∠F should also be 25°
Therefore, the angle on ΔEFG that would prove the triangles are similar is ∠F = 25°.
Answer:
48
Step-by-step explanation:
f(x)= 1/3(4 - x)^2
f(16) = (1/3)(4 - 16)^2
f(16) = (1/3)(-12)^2
f(16) = (1/3)(144)
f(16) = 48