Passing through (9,-9) and perpendicular ti the line whose equation is x -3y-4 =0
1 answer:
Answer:
3x +y -18 = 0
Step-by-step explanation:
The equation of the perpendicular line can be formed from the given equation by swapping the x- and y-coefficients, and negating one of them. The constant in the new equation will be the constant necessary to make the line pass through the given point.
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<h3>swapped coefficients</h3>3x +y +c = 0 . . . . . now both coefficients are positive
<h3>new constant</h3>We want c such that the equation is satisfied at the point (x, y) = (9, -9):
3(9) +(-9) +c = 0
27 -9 +c = 0
c = -18
<h3>equation of perpendicular line</h3>The equation of the desired line is ...
3x +y -18 = 0
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