Question

find the three consecutive odd integers such that the sum of twice the first and three times the second is 67 more than twice the thirdz​

Answer 1

Answer:

  23, 25, 27

Step-by-step explanation:

It can be convenient to work "consecutive integer" problems by using a variable to represent the middle one.

__

setup

Let x represent the middle integer. Then (x-2) is the first of the three odd integers, and (x+2) is the third. The given relation is ...

  2(x -2) +3x = 67 +2(x +2)

solution

  5x -4 = 2x +71 . . . . . simplify

  3x = 75 . . . . . . . . add 4-2x

  x = 25 . . . . . . . divide by 3

The three integers are 23, 25, 27.