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marta [7]
3 years ago
13

If the graph of f(x) = x is shifted up 9 units, what would be the equation of the new graph?

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0

Answer:

f(x) = x + 9

Step-by-step explanation:

y = f(x) + C C > 0 moves it up

To shift it up 9 units

f(x) = x + 9

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Answer:

D.5/1

Step-by-step explanation:

5\1 is just 5 in fraction form

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4 years ago
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TM= 3x + 5 MQ= x + 17 solve for x
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TM=MQ
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-x       -x
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What’s a larger number is two less than four times a smaller. if the sum of the number is 18
s344n2d4d5 [400]
Let x be the larger number and y be the smaller number.
Using the given info, we get
x = 4y - 2
We also know that 
x + y = 18
Substitute x = 4y -2 into x + y = 18
(4y -2) +y = 18
5y - 2 = 18
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6 0
3 years ago
The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

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4 years ago
Why is it important to use significant digits to round the answer
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To get closest to the precise answer
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