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seraphim [82]
2 years ago
15

Please help me with this.

Mathematics
1 answer:
DanielleElmas [232]2 years ago
4 0

Under the assumption of <em>uniform</em> motion, the traveller will travel a distance of 20 feet before slowing down the vehicle to less than 40 miles per second.

<h3>How to calculate the distance taken by traveler before braking</h3>

According to this question, the vehicle travels at <em>constant</em> velocity before the traveler hit the brakes. The distance <em>traveled</em> (s), in feet, is equal to the product of velocity (v), in feet per second, and time (t), in seconds:

s = v · t     (1)

If we know that v = 40 ft/s and t = 0.5 s, then the traveled distance of the vehicle is:

s = (40 ft/s) · (0.5 s)

s = 20 ft

Under the assumption of <em>uniform</em> motion, the traveller will travel a distance of 20 feet before slowing down the vehicle to less than 40 miles per second.

To learn more on uniform motion: brainly.com/question/118814

#SPJ1

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IF YOU HELP ME ILL GIVE YOU A MILLION BUCKS.
Len [333]

Answer:

Here it is solved for rate:

log(1 + rate) = {log(total) -log(Principal)} ÷ Years

Let's work through your example:

log(1 + rate) = {log(6,680) -log(5,000)} / 6

log(1 + rate) = (3.8247764625 -3.6989700043) / 6

log(1 + rate) = 0.020967743

If we raise 10 to the 0.020967743 power

10^0.020967743  it produces 1 plus the rate

1 plus the rate = 10^0.020967743 = 1.0494644773

There fore the rate = .0494644773 which equals

4.94644773 per cent

Source:  https://www.1728.org/compint2.htm

Step-by-step explanation:

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A/2(b+c)(d-e)^2 if a=-10, b=10, c=9, d=2, e=5
bearhunter [10]

Answer:

(-86)

Step-by-step explanation:

\frac{a}{2} (b + c) {(d - e)}^{2}  \\  \\  \frac{ - 10}{2} (10 + 9) {(2 - 5)}^{2}  \\  - 50  - 45 {( - 3)}^{2}  \\  - 50 - 45 (- 3)( - 3) \\  - 50 - 45 + 9 \\  - 95 + 9 = ( - 86)

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