If I'm reading this correctly, it is 2*3*n*n = 6n^2
6n^2 = 54 Divide by 6
n^2 = 54/6
n^2 = 9 Take the square root of both sides.
sqrt(n^2) = sqrt(9)
n = +/- 3
n = + 3 or n = -3. Both will solve the equation above.
Edit
2 * 3 * n * n
Let n = 3
2 * 3 * 3 * 3 = 6 * 9 = 54
The other value is n = - 2
2 * 3 * n * n
2 * 3 * (-3) * (-3) A minus times a minus is a plus.
2 * 3 * 9 = 6 * 9 = 54
both + 3 and - 3 for n will give 54.
Answer:
(a) 100 fishes
(b) t = 10: 483 fishes
t = 20: 999 fishes
t = 30: 1168 fishes
(c)
Step-by-step explanation:
Given
Solving (a): Fishes at t = 0
This gives:
Solving (a): Fishes at t = 10, 20, 30
Solving (c):
In (b) above.
Notice that as t increases from 10 to 20 to 30, the values of decreases
This implies that:
So:
The value of P(t) for large values is:
Answer:
Step-by-step explanation:
The solution to this system of equation is (4, 10)
Answer:
6.0 miles
Step-by-step explanation:
The sequence of distances is a geometric sequence with first term a1 and common ratio (1 +10%) = 1.10. The sum of 7 terms of the sequence is ...
S7 = a1·(r^7 -1)/(r -1)
56.923 = a1·(1.1^7 -1)/(1.1 -1)
5.6923 = a1·0.9487171
Dividing by the coefficient of a1 gives its value:
5.6923/0.9487171 ≈ 5.999997 ≈ 6.000
The hiker traveled 6.0 miles on the first day.
The sequence:
a 1 = 30, a 2 = 70, a 3 = 110, a 4 = 150, a 5 = 190,...
a 2 = a 1 + d
70 = 30 + d
d = 70 - 30 = 40
a n = a 1 + ( n - 1 ) * d
For the 25th month:
a 25 = 30 + 24 * 40 = 30 + 960 = 990
Answer: B ) 990.