2x16 is 32 so you would take square root of 16 out which is 4 and leave the 2 inside. So the answer is 4sqrt(2)
Answer:
74.0°
Step-by-step explanation:
In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree
Solution:
A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.
Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.
Using sine rule, we can find ∠K:

Square root of 36y^3 = √36y^3
= 6√y3
=6∛y
Answer:
<em>m∠2 = 47° </em>
Step-by-step explanation:
m∠1 + m∠2 = 90°
3x + 13 + 5x - 3 = 90
8x + 10 = 90 ⇒ x = 10
<em>m∠2 = 47°</em>
Answer:
16
Step-by-step explanation:
16 grams