<em><u>Question:</u></em>
At the city museum, child admission is $5.80 and adult admission is $9.30. On Monday, four times as many adult tickets as child tickets were sold, for a total sales of $1548.00. How many child tickets were sold that day?
<em><u>Answer:</u></em>
36 child tickets were sold
<em><u>Solution:</u></em>
Given that,
Cost of 1 child admission = $ 5.80
Cost of 1 adult admission = $ 9.30
Let "c" be the number of child tickets sold
Let "a" be the number of adult tickets sold
On Monday, four times as many adult tickets as child tickets were sold
Number of adult tickets sold = four times the number of child tickets
Number of adult tickets sold = 4(number of child tickets sold)
a = 4c ----- eq 1
They were sold for a total sales of $ 1548.00
number of child tickets sold x Cost of 1 child admission + number of adult tickets sold x Cost of 1 adult admission = 1548.00
5.8c + 9.3a = 1548 ---- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
Substitute eqn 1 in eqn 2
5.8c + 9.3(4c) = 1548
5.8c + 37.2c = 1548
43c = 1548
c = 36
Thus 36 child tickets were sold that day
