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poizon [28]
3 years ago
5

What Is The Next Step In This Construction?

Mathematics
2 answers:
alexira [117]3 years ago
7 0
I believe it B hope that helps............
Dmitry [639]3 years ago
3 0
B is the correct answer

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Pedro is building a playground in the shape of a right triangle he wants to know the area of the playground to help him decide h
shusha [124]

Answer:

Amount of sand=Area of triangle(ABC)=1/2*AB*BC

Dimension of rectangle as  length=BC and breadth=AB

Step-by-step explanation:

Given:

Pedro building a playground in shape of right angled triangle.

To Find:

How much sand he need to buy

And if playground changed to rectangle what will be the dimensions.

Solution:

<em>Consider a ΔABC be the play ground vertex of playground,</em>

<em>And AB and BC be the sides making right angle.</em>

The sand required to fill ground will be the amount of are covered by the ABC triangle.

So,

Area Of triangle(ABC)=1/2* base* height

Here base will be BC and height =AB

Therefore Area of Triangle(ABC)=1/2*BC*AB

Depending on the lengths of base and height amount of sand will be decided.

Now,

<em>For Rectangle dimensions,</em>

<em>We know that if same sized triangles composes each other forms a rectangle</em>.

It requires two triangle to form one rectangle as follows

(Refer the attachment)

Same sized Triangle ACD is imposed on it  to from rectangle ABCD.

So dimension for rectangle will be same as the triangle

Dimension=length and breadth

i.e. length=base of triangle=BC

Breadth=Height of triangle=AB

i.e Breadth =AB.

5 0
3 years ago
Is 11/20 greater than a half
jeyben [28]
Yes, as one half or 1/2 is also 10/20. 11/20 is greater than half by a 10% margin.
3 0
3 years ago
Read 2 more answers
Find x and y part 4 for these problems​
Dvinal [7]

Answer:

Step-by-step explanation:

3) Sin30 = 11/x

x = 11/Sin30 = 11/0.5

x = 22

Tan 30 = 11/y

y = 11/tan30 = 11/0.5774

y = 19.1

4) Sin30 = 6/x

x = 6/Sin30 = 6/0.5

x = 12

Tan 30 = 6/y

y = 6/tan30 = 6/0.5774

y = 10.39

5) Sin45 = 9√2/y

y = 9√2/Sin45 = 9√2/(√2/2) =

9√2 × 2/√2 = 18

x = 18

Tan 45 = 9√2/x

x = 9√2/Tan 45 = 9√2/1

x = 9√2

6)

Sin60 = 9/x

x = 9/Sin60 = 9/0.866

x = 10.39

Tan 60 = 9/y/2 = 18/y

1.7321 = 18/y

y = 18/1.7321

y = 10.39

6 0
3 years ago
Orthogonal explanatory variables. suppose in the modelx2 to xk are all uncorrelated. such variables are called orthogonal variab
sertanlavr [38]
<span>d. suppose you have run the regression and afterward you want to introduce another orthogonal variable, say, xk 1 into the model. do you have to recompute all the previous coefficients 1 to k? why or why not?</span>
4 0
4 years ago
Please help with question 2
Rufina [12.5K]

I would distribute first.

-5-3x\geq 2(10+2x)+3

-5-3x\geq 20+4x+3

-5-3x\geq 4x+23

7x \leq -28

x\leq -4

Hope this helps.

頑張って!

6 0
4 years ago
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