Which values could be the values of x and y?

The sum of two numbers is 150 the ratio of the same number is 3:2 find the bigger number

Paladinen [302]

$3x-\ bigger\ number\\
2x-\ smaller\ number\\\\
3x+2x=150\\\\
5x=150\ \ \ | divide\ by\ 5\\\\
x=30\\\\
3x=3*30=90\\\\ Bigger\ number\ is\ 90.$

5 0

3 years ago

HeLp!!

erica [24]

Answer:

C

Step-by-step explanation:

A constant correlation is essentially when the points on a scatter plot do not show any type of pattern or correlation; the points are literally scattered rather randomly, which would cause the graph to neither increase nor decrease.

Meanwhile, a positive correlation means that the points on the plot follow a line with a positive slope. In other words, it increases to the right.

Thus, the answer is C.

Hope this helps!

4 0

3 years ago

Read 2 more answers

The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out

Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So $p = 0.3723$

12 games in November

So $n = 12$

What is the probability that the hockey team wins 6 games in November?

This is $P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505$

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0

3 years ago

How would you find the number, 3/7 of which is equal to t? (let's say it was any number, just need the equation)

ohaa [14]

Let the number be x
(3/7) x = t
I can't think of anything useful to add to this. How about an example?

Let x = 49

(3/7) x = t
(3/7) * 49 = t seven will go into 49
3 * 49 = t
t = 147

8 0

3 years ago

PLS HELP! GIVING BRAINLIST!

svlad2 [7]

Answer:

We conclude that (4, 2) is NOT a solution to the system of equations.

Step-by-step explanation:

Given the system of equations

$y = x - 2$

$y = 3x + 4$

Important Tip:

In order to determine whether (4, 2) is a solution to the system of equations or not, we need to solve the system of equations.

Let us solve the system of equations using the elimination method.

$\begin{bmatrix}y=x-2\\ y=3x+4\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}y-x=-2\\ y-3x=4\end{bmatrix}$

Subtract the equations

$y-3x=4$

$-$

$\underline{y-x=-2}$

$-2x=6$

Now, solve -2x = 6 for x

$-2x=6$

Divide both sides by -2

$\frac{-2x}{-2}=\frac{6}{-2}$

Simplify

$x=-3$

For y - x = -2 plug in x = -3

$y-\left(-3\right)=-2$

$y+3=-2$

Subtract 3 from both sides

$y+3-3=-2-3$

Simplify

$y=-5$

The solution to the system of equations is:

(x, y) = (-3, -5)

Checking the graph

From the graph, it is also clear that (4, 2) is NOT a solution to the system of equations because (-3, -5) is the only solution as we have found earlier.

Therefore, we conclude that (4, 2) is NOT a solution to the system of equations.

8 0

3 years ago

Which values could be the values of x and y? ​

Which values could be the values of x and y?