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butalik [34]
3 years ago
13

Nine times a number decreased by 16

Mathematics
1 answer:
Setler79 [48]3 years ago
7 0

Answer:

9 · x - 16

Explanation:

Nine times a number: 9 · x

Decreased by 16: - 16

Put them together: 9 · x - 16

You might be interested in
Describe the graph of y > mx, where m > 0.
Blizzard [7]

Answer:

that graph will feature an area delimited by a line of slope m passing through the origin (0,0).

Since m>0 the slope is positive, meaning the line goes up.

Since the equation is y > mx, the inequality sign being >, that means the area represented will be ABOVE the line drawn.  

So it will for sure include ALL quadrant II (with -x and +y values) and NONE of the quadrant IV (with +x and -y values) since the line is passing through the origin (0,0).

5 0
3 years ago
Read 2 more answers
The mean blood pressure of the 10 adults in exercise 6 is ?​
Zigmanuir [339]

Snsjwjjwjsjajajjsjdbus

6 0
3 years ago
Help? Show work!
FinnZ [79.3K]

Answer:

m∠ABC = 68°

m∠DEF = 112°

Step-by-step explanation:

Supplementary angles are angles that add up to 180 degrees (they form a straight line).

If ∠ABC and ∠DEF are supplementary, that means that they add up to 180. We can write this in an equation:

  • (6x + 8) + (12x - 8) = 180

Combine like terms.

  • 18x = 180

Divide both sides by 18.

  • x = 10

Find the measure of each angle by substituting 10 for x into both expressions for the angles.

m∠ABC = (6x + 8)°

  • 6(10) + 8 = 68°

m∠DEF = (12x - 8)°

  • 12(10) - 8 = 112°
5 0
3 years ago
Read 2 more answers
Help pls fast
Andrews [41]

Answer:

32.40cm²

Step-by-step explanation:

Given the parallelogram ABCD ;

side AB is always Parallel to CD, hence ;

AB = CD = 7.2cm

Perpendicular from C on AB is the height of the parallelogram = 4.5cm

Area of a parallelogram : base * height

Area of a parallelogram = length base * height

Area of a parallelogram = 7.2 cm * 4.5cm

Area of parallelogram = 32.40cm²

6 0
3 years ago
#4 home do I find which one it is?
lina2011 [118]
\bf \begin{array}{lllll}
solutions&graphs&slopes\\
----&----&----\\
\textit{exactly one}&
\begin{array}{llll}
\textit{the two lines intersect}\\
\textit{at one point}
\end{array}&\textit{different slopes}\\\\
infinitely\quad many&
\begin{array}{llll}
\textit{the two lines coincide}\\
\textit{one is right on top}\\
\textit{ of the other}
\end{array}&
\begin{array}{llll}
\textit{equal slopes}\\
\textit{equal y-intercepts}
\end{array}
\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &
\begin{array}{llll}
\textit{equal slopes}\\
\textit{different y-intercepts}
\end{array}
\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
and               y = -3x + 2
                    y =  m  + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
8 0
4 years ago
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