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ira [324]
2 years ago
12

HELP! A roller coaster starts at a height of 30 meters and rolls down the track. Is this system open or closed?

Physics
1 answer:
Gnom [1K]2 years ago
6 0
Open it would be open not closed
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Answer:Although the nervous system is very complex, nervous tissue consists of just two basic types of nerve cells: neurons and glial cells Neurons are the structural and functional units of the nervous system They transmit electrical signals, called nerve impulses. Glial cells provide support for neurons.

Explanation:

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What best explains the speed of sound in different states of matter? Sound travels fastest in ice because energy is easier to tr
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The speed of sound depends on any form of matter or medium in which sound travels through it and depends on the amount of molecular collisions. Sound travels slowest in gas in the form of steam because the sound has to move around the gas molecules that are far apart making it harder for the energy of vibrations hit the particles and make sound.

Moreover, sound travelling through solids like ice is much faster because the particles are closer together so the sound waves do not have to travel that far making the number of collisions greater and sound spread more easily.

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While skateboarding at 19 km/h throwning a tennis ball at 11 km/h what is the speed of the ball
Lina20 [59]

According to whom ?

So YOU're on your skateboard, and there's somebody else, sitting on HIS porch, watching you skate by on your board.

-- The man on the porch says you're skating by him at 19 km/hr .

-- You throw a tennis ball.  

. . . . . Do you throw it in the same direction that you're skateboarding, or do you throw it away behind you, toward the place you just came from ?

. . . . . Does it fly away from YOU at 11 km/hr ?  Or does it fly past the man on the porch at 11 km/hr ?

There are 4 possible combinations.  One of them is not possible.  Each of the other three combinations leads to two different answers to the question.  And ALL six answers are correct !

1).  You throw the ball forward, in the same direction you're skating.  It flies away from your hand at 11 km/hr.

To you, the speed of the ball is 11 km/hr, in the direction you're skating.  To the man on the porch, it's 30 km/hr, in the direction you're skating.

2). You throw the ball forward, in the same direction you're skating.  It flies past the porch at 11 km/hr.

This isn't possible.

3). You throw the ball backward, toward where you just came from.  It flies away from YOU at 11 km/hr.

To you, the speed of the ball is 11 km/hr, in the direction backward from you.  To the man on the porch, the speed of the ball is 10 km/hr in the direction you're skating.

4).  You throw the ball backward, toward where you just came from.  It flies past the porch at 11 km/hr.

To you, the speed of the ball is 8 km/hr, in the direction backward from you.  To the man on the porch, it's 11 km/hr in the direction you're skating.


NOW you're going to ask me "But what's the REAL speed of the ball ?"

The answer to THAT one is:  There's no such thing !  It all depends on WHO's measuring it ... where that observer is and how HE's moving.

The displacement, speed, velocity, acceleration, and energy of the ball, ALL depend on who's watching it and measuring it.

I'll be interested to see whether you mark this answer 'Brainliest', or report it because it's weird, confusing, and ridiculous.

3 0
4 years ago
The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla
Vladimir [108]

Answer

given,

Radius of sphere = 6.38 × 10⁶ m

time  = 1 day = 86400 s

\omega = \dfrac{2\pi}{T}

\omega = \dfrac{2\pi}{ 86400 }

\omega = 7.272 \times 10^{-5}\ rad/s

a) at equator

v = R_E \omega

v = 6.38 \times 10^6\times 7.272 \times 10^{-5}

v = 464 m/s

acceleration of the person

a = \omega^2R_E

a = (7.272 \times 10^{-5})^2(6.38 \times 10^6)

a = 0.03374 m/s^2

b) at a latitude of 61.0 ° north of the equator.

R = R_E cos \theta

R = 6.38 \times 10^6\times cos 61^0

R = 3.093 \times 10^6 m

v = R \omega

v = 3.093 \times 10^6 \times 7.272 \times 10^{-5}

v = 225 m/s

acceleration of the person

a = \omega^2R_E

a = (7.272 \times 10^{-5})^2(3.093 \times 10^6 )

a = 0.01635 m/s^2

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3 years ago
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