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ira [324]
2 years ago
12

HELP! A roller coaster starts at a height of 30 meters and rolls down the track. Is this system open or closed?

Physics
1 answer:
Gnom [1K]2 years ago
6 0
Open it would be open not closed
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The cheetah, the fastest of land animals, can run a distance of 274 m in 8.65 s at its top speed. What is the cheetahs tips spee
ycow [4]

Answer:

Top speed is 31.68 m/s

Explanation:

Speed of a body is the distance traveled by the body in unit time.

Speed is generally expressed in meter per second or kilometer per hour.

Here, the cheetah travels a distance of 274 m in 8.65 s.

Therefore, speed of cheetah is the distance traveled by it in one second.

For 8.65 s, distance traveled is 274 m

For 1 s, distance traveled will be \frac{274}{8.65} meters per second. This value is called speed.

So, speed is given as the ratio of the distance traveled to that of the time taken.

∴ Top speed of cheetah is given as:

v_{max}=\frac{274}{8.65}=31.68 \textrm{ m/s}

Here, v_{max} is the top speed of cheetah.

7 0
4 years ago
The sources of marine debris and explain why it is a problem with global origins
Lera25 [3.4K]
Marine debris is any trash or litter that ends up in a marine environment. This harms wildlife through entanglement, ingestion, and disturbs the habitat of many species of animals. This becomes a global problem when it is a danger to human health. Nails, syringes, and glass can cause harm to people on the beach. On top of that, trash in the waterway increases the amount of chemicals destroying our water quality.
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4 0
3 years ago
A bullet with a mass ????b=13.5mb=13.5 g is fired into a block of wood at velocity ????b=253vb=253 m/s. The block is attached to
Lorico [155]

Answer:

450 grams

Explanation:

Given:

mass of the bullet, m = 13.5 g = 0.0135 kg

velocity of the bullet, v = 253 m/s

spring constant of the spring, k = 205 N/m

Compression of the spring, x = 35.0 cm = 0.35 m

Now, the kinetic energy of the moving system (bullet + board) will tend to move the spring

thus,

let velocity of the system, V

now, applying the concept of conservation of momentum, we have

mv = (M + m)V

where,

M is the mass of the block

thus,

V = mv/(M + m)

now,

the kinetic energy of the system = (1/2)(M + m)V²

or

the kinetic energy of the system = (1/2)(M + m)(mv/(m + M))²

Energy gained by the spring = (1/2)kx²

now,

equating both the energies, we get

(1/2)(M + m)(mv/(m + M))² = (1/2)kx²

or

(mv)²/(m + M) = kx²

on substituting the values, we get

(0.0135 × 253)²/(0.0135 + M) = 205 × (0.35)²

or

11.66/(0.0135 + M) = 25.1125

or

M = 0.450 kg = 450 grams

8 0
4 years ago
Suppose that a comet has a very eccentric orbit that brings it quite close to the Sun at closest approach (perihelion) and beyon
Nutka1998 [239]

Answer:

16.63min

Explanation:

The question is about the period of the comet in its orbit.

To find the period you can use one of the Kepler's law:

T^2=\frac{4\pi}{GM}r^3

T: period

G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2

r: average distance = 1UA = 1.5*10^11m

M: mass of the sun = 1.99*10^30 kg

By replacing you obtain:

T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min

the comet takes around 16.63min

8 0
3 years ago
Can you help me I am in trouble plz help ​
kupik [55]

Answer:

A velocity

B acceleration

C ms^-2

6 0
3 years ago
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