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Deffense [45]
3 years ago
11

Net force of 200 newtons is applied to a wagon for 3 seconds

Physics
1 answer:
AveGali [126]3 years ago
6 0

Momentum of the wagon increases by (200 x 3)

                                                     = 600 newton-sec

                                                     = 600 kg-m/sec
 
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If you need 40.0 Nm of torque in order to loosen a nut on a wn
KonstantinChe [14]

Answer:

0.301 m

Explanation:

Torque = Force × Radius

τ = Fr

40.0 Nm = 133 N × r

r = 0.301 m

The mechanic must apply the force 0.301 m from the nut.

6 0
2 years ago
What does frequency describe?
ddd [48]

The whole definition of frequency is:  <em>How often something happens.  </em>

Especially referring to something that happens over and over and over and over.

One example is Choice-C: How often the particles of a medium vibrate.

"Frequency" comes from the word "frequent".  That means "often", and "frequency" just means "often-ness" ... HOW often the thing happens.

Some other examples:

Frequency of jump-roping . . . maybe 60 per minute .

Frequency of rain . . . maybe 5 per month .

Frequency of an AM radio station . . . maybe 1 million waves per second.

(If it's something <u><em>per second</em></u>, then we call it "Hertz".  That's not for the car rental company.  It's for Heinrich Hertz, the German Physicist who was the first one to prove that electromagnetic waves exist.  He sent radio waves all the way ACROSS HIS LABORATORY and detected them at the other side ( ! ), in 1887.)

Frequency of the wiggles in the sound wave coming out of a trumpet playing the note ' A ' . . . 440 Hertz.

Frequency of sunrise and the Chicago Tribune newspaper . . . 1 per day

Frequency of the cycle of Moon phases and an average human woman's ovulation cycle: 1 per 29.531 days, 1 per ~28 days .

7 0
2 years ago
Read 2 more answers
Which of the following is an example of a chemical change?
ss7ja [257]

Answer:

Burning Paper

Explanation:

This is a chemical reaction, because new substances are formed

6 0
2 years ago
The motion of a particle is described by the position function s(t) = 2t - 15t +33t+17,t&gt;0 , where is measured in seconds and
8090 [49]

The time when the particle is at rest is at 1.63 s or 3.36 s.

The velocity is positive at when the time of motion is at 0.

The total distance traveled in the first 10 seconds is 847 m.

<h3>When is a particle at rest?</h3>
  • A particle is at rest when the initial velocity of the particle is zero.

The time when the particle is at rest is calculated as follows;

s(t) = 2t³ - 15t² + 33t + 17

v = \frac{ds}{dt} = 6t^2 -30t + 33\\\\at \ rest, \ v = 0\\\\6t^2 - 30t + 33 = 0\\\\6(t- \frac{5}{2} )^2- \frac{9}{2} = 0\\\\t = 1.63\ s \ \ or \ 3.36 \ s

The velocity is positive at when the time of motion is as follows;

0.

The total distance traveled in the first 10 seconds is calculated as follows;

2(10)^3 - 15(10)^2 + 33(10) + 17 = 847 \ m

Learn more about motion of particles here: brainly.com/question/11066673

4 0
2 years ago
A closed system consisting of 2 lb of a gas undergoes a process during which the relation between pressure and volume is pVn = c
vazorg [7]

Answer:

V1=<u>2.5ft3</u>

<u>V2=1ft3</u>

n=1.51

Explanation:

PART A:

the volume of each state is obtained by multiplying the mass by the specific volume in each state

V=volume

v=especific volume

m=mass

V=mv

state 1

V1=m.v1

V1=2lb*1.25ft3/lb=<u>2.5ft3</u>

state 2

V2=m.v2

V2=2lb*0.5ft3/lb=  <u> 1ft3</u>

PART B:

since the PV ^ n is constant we can equal the equations of state 1 and state 2

P1V1^n=P2V2^n

P1/P2=(V2/V1)^n

ln(P1/P2)=n . ln (V2/V1)

n=ln(P1/P2)/ ln (V2/V1)

n=ln(15/60)/ ln (1/2.5)

n=1.51

8 0
3 years ago
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