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azamat
3 years ago
14

Can you help me I am in trouble plz help ​

Physics
1 answer:
kupik [55]3 years ago
6 0

Answer:

A velocity

B acceleration

C ms^-2

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La ce distanta de la suprafata Pamintului intensitatea cimpului sau gravidational este egala cu 1 N/kg ?
Ulleksa [173]
Acceleration of gravity is proportional to  1/D² .
('D' is the distance from the Earth's center.)

We need  (D / R)² = 9.8
('R' is the Earth's radius.)

D/R = √9.8 = 3.13

Distance from Earth's <u>center</u> = 3.13 R
Distance above Earth's <u>surface</u> = 2.13 R = about 13,570 km =====================================================

<span>Accelerarea de gravitate este proporțională cu 1 / D².
('D este distanța de centrul Pământului.)

Avem nevoie de (D / R) ² = 9,8
('R' este raza Pământului.)</span><span>

D / R = √9.8 = 3,13

Distanța de la <u>centrul</u> Pamantului = 3,13 R
Distanța de deasupra <u>suprafetei</u> Pamantului = 2.13 R = aproximativ <span><em>13,570 km</em></span></span>
6 0
4 years ago
What is the voltage at resistor #3? (must include unit - V)
Romashka-Z-Leto [24]

Explanation:

I = 120/30=2A

Voltage across R3= current × resistance

= 2A × 15 ohm = 30 volt

5 0
3 years ago
In the video, you saw NASA launch a rocket carrying a rover to Mars. What is the mission of the Mars land rover, and why is it i
Darya [45]
The Curiosity rover launched<span> on a two-stage Atlas V-541 </span>launch<span> vehicle, provided by United </span>Launch<span>Alliance, a joint venture of Boeing Co. and Lockheed Martin Corp.</span>
3 0
3 years ago
Read 2 more answers
Can someone please help me I will mark you as brilliant.
Svet_ta [14]

Answer:

1=8 ohms 2=0.5 Amps

Explanation:

4 0
3 years ago
The block in the diagram below is AT REST. However, the tension in the cable is not the only thing holding the block back. Stati
Vedmedyk [2.9K]

Answer:

The  tension in the rope is 229.37 N.

Explanation:

Given:

Mass of the block is, m=33.2\ kg

Coefficient of static friction is, \mu = 0.214

Angle of inclination is, \theta = 31.5°

Draw a free body diagram of the block.

From the free body diagram, consider the forces in the vertical direction perpendicular to inclined plane.

Forces acting are mg\cos \theta and normal N. Now, there is no motion in the direction perpendicular to the inclined plane. So,

N=mg\cos \theta\\N=(33.2)(9.8)\cos (31.5)\\N=277.415\ N

Consider the direction along the inclined plane.

The forces acting along the plane are mg\sin \theta and frictional force, f, down the plane and tension, T, up the plane.

Now, as the block is at rest, so net force along the plane is also zero.

T=mg\sin \theta+f\\T=mg\sin \theta +\mu N\\T= (33.2)(9.8)(\sin (31.5)+(0.214\times 277.415)\\T= 170+59.37\\T=229.37\ N

Therefore, the  tension in the rope is 229.37 N.

3 0
3 years ago
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