For solving this we need the change in distance and the change in time. You said that the change in time is 1.8 seconds and the change in distance is 3.6 meters. ( This is assuming it started at 0 meters and started at 0 seconds )
Since the starting was 0,0 we can toss them out as they add no value. Now since speed is labeled (in this case) m/s, we divide how many meters it traveled over how many seconds it took to travel it.
3.6 / 1.8 = 2
The average speed of the cart is 2 m/s
Answer:
Graph 1, 2, 5, 6 are not functions.
Graph 3, 4 are functions
Step-by-step explanation:
For every input there can only be one output to be a function.
Answer:
6
Step-by-step explanation:
xy=k
Value of k ; when ; x = - 3 and y = - 2
Put x = - 3 and y = - 2 into the equation :
(-3)(-2) = k
-3 * - 2 = k
6 = k
The constant of variation k = 6
I assume that you want to know the temperature at a certain timing.
Well, you know that at 12:00 pm, the temperature was 12 F and that it decreases by a steady rate of 2 F each hour.
This means that at 1:00 pm, the temperature was 12-2 = 10 F
At 2:00 pm, the temperature was 10-2 = 8 F
At 3:00 pm, it was 8-2 = 6 F
.......and so on
You can follow this sequence to the timing you are looking for.
