We are concern about the vector (x-x0, y-y0, z-z0)
equaling to 5.
This happens
when √(x-x0)^2 + (y-y0)^2 + (z-z0)^2 = 5
Square
both side:
(x-x0)^2
+ (y-y0)^2 + (z-z0)^2 = 25 , a sphere
Which you will
recognize as a circle of radius one centered at (x0, y0, z0)
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Answer:
The domain is correct
but the correct range is (-3 , 2)
If (x+5) is a factor the equation will equal zero when x=-5 so
3(-5^2)+14(-5)+k=0
75-70+k=0
5+k=0
k=-5
1. -2x + 3y + 5
A. -x + -x + y + y + y + 1 + 1 + 1 + 1 + 1
B. -x + -x + 2y + y + 4 + 1
D. -5x + 3x + 4y - y + 4 + 1
2. -$40 + 100 = $60 - $50 = $10
Cindy currently has $10 left in her bank account.
