We have that
f²{k^6/[k^4*k^3]}^-3
step 1
f²{k^6/[k^(4+3)]}^-3---------> f²{k^6/[k^7]}^-3-------> step 1 is correct
step 2
f²{k^6/[k^7]}^-3------> f²{k^(6-7)]}^-3----> f²{k^(-1)}^-3----> step 2 is correct
step 3
f²{k^(-1)}^-3------> f²{k^[(-1)*(-3)]}-----> f²{k^(3)}
therefore
Martha made a mistake in the step 3
the answer is
step 3
f²k³
Answer:
6: d, 7: b and c, 8: a
Step-by-step explanation:
6) The answer is (d).
We have,
0.00001131 =1.131×0.00001
= 1.131/100000
= 1.131×10^-5.
So, this is correct answer.
7) This question have two answers (b) and (c), both are correct.
(b) 480000-97000
= 4.8x100000-9.7x10000
=4.8x10^5-9.7x10^4
(c) 4.8x10^5-9.7x10^4
= 4.8x10^5-0.97x10^5
= (4.8-0.97) x10^5
=3.83x10^5
8)(a)
(4 x 10^3)(5x10^7).
= 4x5x10³x10^7
= 4x5x10^(3+7).
