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irina1246 [14]
1 year ago
14

What is electromicro scopekoi hai kya -_-​

Biology
1 answer:
garik1379 [7]1 year ago
3 0

Explanation:

a microscope with high magnification and resolution, employing electron beams in place of light and using electron lenses.

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18
Usimov [2.4K]

Answer:

Explanation:

Ok first. Are you from mr.goodfriend's class? cause i know a safina and you questions are almost the same as the quiz thats due tommorow. Oh and it's b i think

5 0
2 years ago
Florida is hot most of the year. Will a cougar show seasonal changes?
rusak2 [61]

Answer:

No, because the cougar can always find a food source in Florida.

Explanation:

Brainliest pls :)

5 0
2 years ago
Read 2 more answers
The most important dietary approach for the treatment of type 2 diabetes mellitus is to
Doss [256]
Lose body fat or weight. 

Losing weight, even 10-20% can reduce your risk of diabetes and lead to the treatment of it.
4 0
3 years ago
Read 2 more answers
When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red
Pavlova-9 [17]

Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

  • RR- red
  • ww - white
  • Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

<u>From this cross the expected ratios are:</u>

  • 1/4 RR (red)
  • 2/4 Rw (pink)
  • 1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3><u>Chi square test</u></h3>

X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}

<u>The observed frequencies were:</u>

  • 34 Red
  • 76 Pink
  • 40 White

Total 150

<u>The expected frequencies for our null hypothesis are:</u>

  • 1/4 x 150 = 37.5 Red
  • 2/4 x 150 = 75 Pink
  • 1/4 x 150 = 37.5 white

X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}

X^2=0.5067

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

8 0
3 years ago
Need Help). Question 1): Photosynthesis and cellular respiration are often described in two ways: 1) they are chemically opposit
Zinaida [17]

Answer:

too long don't wanna read all of it

Explanation:

plus cod vanguards just came out going to play that game 24/7

7 0
2 years ago
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