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2 years ago

Which equation is equivalent to StartRoot x squared + 81 EndRoot = x + 10?

Mathematics

1 answer:

marishachu [46]2 years ago

5 0

The given equation is equivalent to Option D .

The mission option is

A. x+10= x+10

B. x+9 =x² + 20x + 100

C. x² +81 = x² + 100

D. x² + 81 = x² +20x + 100

<h3>What is an Equation ?</h3>

An equation is a mathematical statement formed when two algebraic expression is equated by an equal sign .

An equation is given in the question

$\rm \sqrt{x^2 + 81} = x +10$

$\rm {x^2 + 9^2} = (x +10)^2$

$\rm {x^2 + 81} = x^2 +20x + 100$

Therefore the given equation is equivalent to Option D .

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Solve for the x using elimination <br> 3x-2y=13x−2y=1 <br> 2x+2y=42x+2y=4

Nikitich [7]

3x - 2y = 1

2x + 2y = 4

Add the second equation to the first

5x = 5

2x + 2y = 4

Divide the first equation by 5

x = 1

2x + 2y = 4

Subtract the first equation from the second

x = 1

x + 2y = 3

Subtract the first equation from the second again

x = 1

2y = 2

Divide the second equation by 2

x = 1

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<h3>So, the solution is x = 1 and y = 1 {or: (1, 1)} </h3>

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3 years ago

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marishachu [46]

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8 0

3 years ago

Use the drop-down menus to choose the correct locations on the number line.

erastova [34]

Answer:

i) Point B is located at 0.

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iii) Point D is located at 35.

iv) -20 is one tick mark to the left of point A.

3 0

3 years ago

Sam is handing out advertisements for an upcoming event. He starts with a box of 5,000 advertisements and hands out 12 advertise

lawyer [7]

Answer:

n = 5,000 - 12t

Step-by-step explanation:

Sam is handing out advertisements for an upcoming event.

No of advertisements = 5000

No of advertisements per minute is 12.

We need to find the equation that best models the relationship between the amount of time t, Sam spends handing out advertisements and the number of advertisements, n, remaining.

5000 is fixed and there are 12 advertisements per minute. Let the equation is given by :

n = 5,000 - 12t

Hence, the correct option is (d).

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3 years ago

PLEASE HELP ME!

Ganezh [65]

42.8% players practised more than one time a week

Step-by-step explanation:

Total no of players practising = 7

Players who practice more than once a week= 3

(According to graph player no 1,3 and 5 played more than once in a week)

To find the percentage of the players who practised more than one time a week

The formula used is:

percentage of players practising more than one time a week= ( no of player playing more than once / total no of players ) x 100%

Putting values in the formula

percentage of players playing more than one time a week= $3/7x100%$ %

= $0.428x100%$ %

= 42.8%

So, 42.8% players practised more than one time a week

Keywords: Calculation of percentage

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3 years ago