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3 years ago

Sum 2 5/8 + 4 1/8 = ?

Mathematics

2 answers:

yan [13]3 years ago

8 0

Answer:

6 6/8, simplified to 6 3/4

Step-by-step explanation:

First, add the whole numbers. 2+4 = 6. Next, add the fractions. In this example the denominators are the same so you simply add the numerators (when summing two fractions you don't add the denominators). So 5/8 + 1/8 = 6/8, which you can simplify to 3/4. Add the 6 from the first step to that, and you get 6 3/4

Lostsunrise [7]3 years ago

4 0

Answer:

6 6/8 OR 6 3/4

Step-by-step explanation:

2 5/8 +4 1/8

6 6/8

SImplify= 6 3/4

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QUIZ

stepan [7]

eliminating y

x - y = -5

3x + y = 1

________ +

4x = -4

x = -1

eliminating x

• x - y = -5 ....... (x3)

3x + y = 1 ....... (x1)

• 3x - 3y = -15

3x + y =1

___________ -

-4y = -16

y = 4

A. (-1, 4)

3 0

3 years ago

What is a reasonable rage for this situation?

drek231 [11]

Answer:

Root is x=16 Domain and Range would be all real numbers

Step-by-step explanation:

3 0

3 years ago

Find two consecutive even numbers such that the difference of one half the larger and two fifths the smaller is equal to five.

kirill [66]

The answer would be this 1/2(n+2)-2/5n=5

6 0

3 years ago

Read 2 more answers

There are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom. The three candidates that rece

sveticcg [70]

Answer:

Step-by-step explanation:

Given that there are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom.

The three candidates that receive the highest number of votes become candidates for a runoff election.

i.e. 3 persons out of 8 to be selected for becoming candidates for a runoff election.

Since order does not matter we use combinations here

3 persons out of 8 can be done in 8C3 ways

= 56

no of 3-candidate combinations possible are 56

3 0

3 years ago

A toy rocket is launched from a platform that is 48 ft high. The rocket height above the ground is modeled by h=-16t^2+32t+48. a

Komok [63]

Answer:

a) 64 feet

b) 3 seconds

Step-by-step explanation:

The maximum height of $h=h(t)$ can be bound by finding the y-coordinate of the vertex of $y=-16x^2+32x+48$ .

Compare this equation to $y=ax^2+bx+c$ to find the values of $a,b,\text{ and } c$ .

$a=-16$

$b=32$

$c=48$ .

The x-coordinate of the vertex can be found by evaluating:

$\frac{-b}{2a}=\frac{-32}{2(-16)$

$\frac{-b}{2a}=\frac{-32}{-32}$

$\frac{-b}{2a}=1$

So the x-coordinate of the vertex is 1.

The y-coordinate can be found be evaluating $y=-16x^2+32x+48$ at $x=1$ :

$y=-16(1)^2+32(1)+48$

$y=-16+32+48$

$y=16+48$

$y=64$

So the maximum height of the rocket is 64 ft high.

When the rocket hit's the ground the height that the rocket will be from the ground is 0 ft.

So we are trying to find the second t such that:

$0=-16t^2+32t+48$

I'm going to divide both sides by -16:

$0=t^2-2t-3$

Now we need to find two numbers that multiply to be -3 and add to be -2.

Those numbers are -3 and 1 since (-3)(1)=-3 and (-3)+(1)=-2.

$0=(t-3)(t+1)$

This implies we have either $t-3=0$ or $t+1=0$

The first equation can be solved by adding 3 on both sides: $t=3$ .

The second equation can be solved by subtracting 1 on both sides: $t=-1$ .

So when $t=3$ seconds, is when the rocket has hit the ground.

5 0

2 years ago