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ira [324]
3 years ago
12

Sum 2 5/8 + 4 1/8 = ?

Mathematics
2 answers:
yan [13]3 years ago
8 0

Answer:

6 6/8, simplified to 6 3/4

Step-by-step explanation:

First, add the whole numbers. 2+4 = 6. Next, add the fractions. In this example the denominators are the same so you simply add the numerators (when summing two fractions you don't add the denominators). So 5/8 + 1/8 = 6/8, which you can simplify to 3/4. Add the 6 from the first step to that, and you get 6 3/4

Lostsunrise [7]3 years ago
4 0

Answer:

6 6/8 OR 6 3/4

Step-by-step explanation:

2 5/8 +4 1/8

6 6/8

SImplify= 6 3/4

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QUIZ
stepan [7]

eliminating y

x - y = -5

3x + y = 1

________ +

4x = -4

x = -1

eliminating x

• x - y = -5 ....... (x3)

3x + y = 1 ....... (x1)

• 3x - 3y = -15

3x + y =1

___________ -

-4y = -16

y = 4

A. (-1, 4)

3 0
3 years ago
What is a reasonable rage for this situation?
drek231 [11]

Answer:

Root is x=16 Domain and Range would be all real numbers

Step-by-step explanation:

3 0
3 years ago
Find two consecutive even numbers such that the difference of one half the larger and two fifths the smaller is equal to five.
kirill [66]
The answer would be this  1/2(n+2)-2/5n=5
6 0
3 years ago
Read 2 more answers
There are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom. The three candidates that rece
sveticcg [70]

Answer:

56

Step-by-step explanation:

Given that there are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom.

The three candidates that receive the highest number of votes become candidates for a runoff election.

i.e. 3 persons out of 8 to be selected for becoming candidates for a runoff election.

Since order does not matter we use combinations here

3 persons out of 8 can be done in 8C3 ways

= 56

no of 3-candidate combinations  possible are 56

3 0
3 years ago
A toy rocket is launched from a platform that is 48 ft high. The rocket height above the ground is modeled by h=-16t^2+32t+48. a
Komok [63]

Answer:

a) 64 feet

b)  3 seconds

Step-by-step explanation:

a)

The maximum height of h=h(t) can be bound by finding the y-coordinate of the vertex of y=-16x^2+32x+48.

Compare this equation to y=ax^2+bx+c to find the values of a,b,\text{ and } c.

a=-16

b=32

c=48.

The x-coordinate of the vertex can be found by evaluating:

\frac{-b}{2a}=\frac{-32}{2(-16)

\frac{-b}{2a}=\frac{-32}{-32}

\frac{-b}{2a}=1

So the x-coordinate of the vertex is 1.

The y-coordinate can be found be evaluating y=-16x^2+32x+48 at x=1:

y=-16(1)^2+32(1)+48

y=-16+32+48

y=16+48

y=64

So the maximum height of the rocket is 64 ft high.

b)

When the rocket hit's the ground the height that the rocket will be from the ground is 0 ft.

So we are trying to find the second t such that:

0=-16t^2+32t+48

I'm going to divide both sides by -16:

0=t^2-2t-3

Now we need to find two numbers that multiply to be -3 and add to be -2.

Those numbers are -3 and 1 since (-3)(1)=-3 and (-3)+(1)=-2.

0=(t-3)(t+1)

This implies we have either t-3=0 or t+1=0

The first equation can be solved by adding 3 on both sides: t=3.

The second equation can be solved by subtracting 1 on both sides: t=-1.

So when t=3 seconds, is when the rocket has hit the ground.

5 0
2 years ago
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