Answer:
x = 0
y = -2
Step-by-step explanation:
The given system of equation are:
5x + y = -2
2x - 2y = 4
The problem here is to find x and y from the expression
5x + y = -2 ----- i
2x - 2y = 4 ---- ii
So;
i x 2 : 10x + 2y = -4 ---- iii
ii x 5 : 10x - 10y = 20 ----- iv
iii - iv; 12y = -24
y = -2
Now find x;
5x + y = -2
5x - 2 = -2
x = 0
Answer:
8x-20
Step-by-step explanation:
Distribute:
=(6)(2x)+(6)(−3)+(−2)(2x)+(−2)(1)
=12x+−18+−4x+−2
Combine Like Terms:
=12x+−18+−4x+−2
=(12x+−4x)+(−18+−2)
=8x+−20
Answer:
=8x−20
5 with some change left over.
Answer:
(a) 283 days
(b) 248 days
Step-by-step explanation:
The complete question is:
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?
Solution:
The random variable <em>X</em> can be defined as the pregnancy length in days.
Then, from the provided information
.
(a)
The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:
P (X > x) = 0.11
⇒ P (Z > z) = 0.11
⇒ <em>z</em> = 1.23
Compute the value of <em>x</em> as follows:

Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.
(b)
The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:
P (X < x) = 0.05
⇒ P (Z < z) = 0.05
⇒ <em>z</em> = -1.645
Compute the value of <em>x</em> as follows:

Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.
Area (square)=side²
therefore:
side²=200 feet²
side=√(200 feet²)=14.142 feet≈14.1 feet.
solution: side of square=14.1 feet.