Basically you have to solve for the value of Y when x= 4
So you have -5y= 11 - 2x
y = -11/5 + 2/5x
therefore when x = 4 , y = -3/5
P1. C
P2. A
3.D i think
4. C and D maybe
QUESTION → 
Start by subtracting 3 from both sides to get
.
Now multiply both sides by the reciprocal of 3/2, which is 2/3.
On the left, we have x, and on the right, -3(2/3) is -2.
So we have x = -2.
12/35 unless you simplify it
You want to isolate the x-term from the constant term, so you can subtract x/3 and add 10. This gives you
... 4/9x -10 -x/3 +10 > x/3 -12 -x/3 +10
... 1/9x > -2 . . . . . . collect terms
Now, you can multiply by 9 to see the condition on x.
... 9(1/9x) > -2(9)
... x > -18
On the x-y plane, the graph of this will be a dashed line at x=-18, and the half-plane to the right of that line will be shaded.
On a number line, there will be an open circle at x=-18, and the number line to the right of that circle will be marked (bold, colored, shaded, whatever).