Step-by-step explanation:
We are asked to simply (2√5 + 3√2)². Using formula: (a + b)² = a² + b² + 2ab. Let's say 2√5 = a, 3√2 = b. So,
→ (a + b)² = a² + b² + 2ab
→ (2√5 + 3√2)² = (2√5)² + (3√2)² + 2(2√5)(3√2)
We are aware about the fact that root means 1/2 and square of root means 2/2 that is 1. Using this we get:
→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2√5)(3√2)
Solve the brackets, to do so first put the like terms in one box.
→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2*3)(√5)(√2)
Solve the rest calculations.
→ (2√5 + 3√2)² = 20 + 18 + 2(6)(√10)
→ (2√5 + 3√2)² = 38 + 12√10
Option (a) (38 + 12√10) is the correct option.
Step-by-step explanation:
Given function is y = –x.
Substitute the values of x in the function and find the values of y.
y = –x
At x = –2,
y = –(–2) = 2
At x = –1,
y = –(–1) = 1
At x = 0,
y = –(0) = 0
At x = 1,
y = –1(1) = –1
At x = 2,
y = –(2) = –2
Now, substitute the values of y in the table.
The image of the table is attached below.
Answer:
x = 75 m
Step-by-step explanation:
This is a problem of similar triangles solved using proportions.
In similar triangles, corresponding side lengths are proportional.
Here the small and large triangles are similar because the have all three angles congruent.
By proportions, identifying corresponding sides,
x/45 = 50/30
solve for x
x = 45*(50/30) = 75 m
Answer:
D) -20/-5 because a negative divided by a negative is a positive.
Step-by-step explanation:
Answer: a) √50
b) n = 1 + 7i
Step-by-step explanation:
first, the modulus of a complex number z = a + bi is
IzI = √(a^2 + b^2)
The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:
m = 2 + 6i
n = a + bi
Im + nI = 3√10
Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10
= √(a^2 + b^2 + 40) = 3√10
a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90
a^2 + b^2 = 90 - 40 = 50
√(a^2 + b^2 ) = InI = √50
The modulus of n must be equal to the square root of 50.
now we can find any values a and b such a^2 + b^2 = 50.
for example, a = 1 and b = 7
1^2 + 7^2 = 1 + 49 = 50
Then a possible value for n is:
n = 1 + 7i
