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NARA [144]
3 years ago
6

During a science experiment, the temperature of a certain substance was recorded at three different times. Use this information

to complete the statements below. The time at which the temperature is below 0°C is ___ (3:00,4:00,5:00) The time with the highest temperature is ___(3:00,4:00,5:00) The temperature at 3:00 is ____(closer too, farther from) 0°C than is the temperature at 4:00. HELP ASAP

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0

Answer:

Step-by-step explanation: The time at which the temperature is below 0°C is 3:00

The time with the highest temperature is 4:00 The temperature at 3:00 is closer too zero than the temp at 4:00

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Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than M
victus00 [196]

Answer:

6 miles

Step-by-step explanation:

From the above question:

Stan ran 4 and StartFraction 7 Over 10 EndFraction miles

The number of miles stan ran =

4 7/10 miles

We are also told that this number of miles was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran.

Let the number of miles Matt ran = m

Hence,

4 7/10 miles = m - 1 3/10

m = 4 7/10 + 1 3/10

m = (4 + 1) + ( 7/10 + 3/10)

m = 5 + (7 + 3/10)

m = 5 + (10/10)

m = 5 + 1

m = 6 miles

Therefore, the number rod miles Matt ran was 6 miles

7 0
3 years ago
If the measure of angle ABD is 100, what is the measure of angle ABC
AURORKA [14]

i dont know. Im sorry about that.

3 0
4 years ago
a falling stone is at a certain instant 230 feet above the ground. 3 seconds later it is only 14 feet above. From what height wa
vazorg [7]
The falling stone is a certain instant 230 feet above the ground. 3 seconds later it is only 14 feet above. The height that it was dropped is 32 feet. The equation for the answer is; 

<span>16<span>t2</span>+<span>h0</span>=230</span> <span>−16(t+3<span>)2</span>+<span>h0</span>=14</span>


4 0
3 years ago
Read 2 more answers
What is the perimeter of a polygon with vertices at (−2, 1) , ​ (−2, 4) ​, (2, 7) , ​ (6, 4) ​, and (6, 1) ​?
alekssr [168]
First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
d =  \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }
d1 =  \sqrt{{(1 - 4)}^{2} + {( - 2 -  - 2)}^{2} } \\  =  \sqrt{{(- 3)}^{2} + {(0)}^{2} } =  \sqrt{9}  \: = 3
d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\  = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } =  \sqrt{9 + 16}  \\  =  \sqrt{25}  \: = 5
d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\  =  \sqrt{{(3)}^{2} +  {( - 4)}^{2} } =  \sqrt{9 + 16}  \\  =  \sqrt{25} \:  = 5
d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\  =  \sqrt{ {(3)}^{2} +  {(0)}^{2}  }  =  \sqrt{9} \:  = 3
d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} }  \\ =  \sqrt{ {(0)}^{2} +  {( - 4)}^{2}} =  \sqrt{16}  \:  = 4
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units





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3 years ago
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100,435 hope this helps you
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