Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Do u mean a mixed number?
2 2/5
Answer:
pd 6 13.25
Step-by-step explanation:
Hello there awesome brainly user!
To convert
to a mixed number you have to divide 31/6 which equals 5 R 1 Remember that the remainder is the numerator and the whole number is 5. So, the mixed fraction is
For further info, message me
Thanks and have a good day.
Answer:
What is the surface
Step-by-step explanation:
U should put a pic or something so we can help u <3 btw can u give me a brainllest cuz i need 1 more to hit 5 thank u <3
