Answer: 29.916 minutes
Step-by-step explanation:
Given the following :
Mean of distribution = 17.8 minutes
Standard deviation of distribution = 5.2 minutes
Percentage of customers to give free lube and oil change service should not exceed 1% if the customer waits beyond the guaranteed time ;
Length of guarantee :
Since % of customers should not exceed 1%
Then probability of not being chosen = (1 - 0.01) = 0.99
Using the z table to find the Zscore of 0.99,
Zscore of 0.99 = 2.33
This is 2.33 standard deviations above the mean
(2.33 × standard deviation) + mean value
(2.33 × 5.2 minutes) + 17.8 minutes
12.116 + 17.8
= 29.916 minutes
Answer:
C
Step-by-step explanation:
when you solve this it is x>10.
< and > is the open hole and x is greater than -10 so it will be going right.
hope this helped :)
Answer:
0
Step-by-step explanation:
32=32+0
Shjdkkakskskakshsgsisuelwis code also
Answer:
5:20pm
Step-by-step explanation:
120+100=320minutes
320/60=5hrs 20min
12+5:20= 17:20pm or 5:20pm
