Question

le="\sf\large\green{\underbrace{\red{Question*}}}:" alt="\sf\large\green{\underbrace{\red{Question*}}}:" align="absmiddle" class="latex-formula">
$\mathcal \pink{Solve}$
$\blue{3(x - 2) + 2(x + 1) = 10}$
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Answer 1

$\large{\underline{\underline{\pmb{\sf{\color {red}{Solve:}}}}}}$

$\sf \red{3(x - 2) + 2(x + 1) = 10}$

$\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}$

In the above question, it is said to find out the value of "x". So, let's solve.

First we gonna multiply (x - 2) with 3 and then again (x + 1) with 2.

So, it goes...

$3(x - 2) + 2(x + 1) = 10 \\ \\ \implies \: 3x - 6 + 2x + 2 = 10 \\ \\ \implies \: 5x - 4 = 10 \\ \\ \implies \: 5x = 10 + 4 \\ \\ \implies5x = 14 \\ \\ \implies \: x = \frac{14}{5} \\ \\ \implies \: x = 2.8$

Therefore, we've found the value of "x" and that is 2.8

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Answer 2

$~~~~~~~3(x-2) +2(x +1) = 10\\\\\implies 3x -6 + 2x+2 = 10\\\\\implies 5x -4 = 10\\\\\implies 5x = 10+4\\\\\implies 5x = 14 \\\\ \implies x = \dfrac{14}5 \\\\ \implies x = 2.8$