What are the critical values X2/L and X2/R that correspond to a 99% confidence level and a sample size of 30?

High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers

Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

Step:-1

Given that the mean of the Population = 540HP

Given that the size of the sample 'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

Step(ii):-

Degrees of freedom = n-1 =9-1 =8

t₀.₀₀₅ = 3.3554

The 99% of a confidence interval for the average maximum HP for the experimental engine.

$(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2} + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )$

$(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )$

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

Final answer :-

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

4 0

3 years ago

647.2 + 12.88 how to answer that step by step

IgorC [24]

Answer:

660.08

Step-by-step explanation:

1. first you will need to line up the decimals and make sure the places are correct

647.2

+ 12.88

2. Then you just add them

4 0

3 years ago

Please help thanks Xxxxx

Stells [14]

Answer:

A

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Determine the value of the variable in the simplified expressions. What is the value of X? Gx+h^-3=1/g^6+1/h^3. X=_____. What is

swat32

Answer:

x=-6

y=4

Step-by-step explanation:

i just took the quiz

hope i could help

5 0

3 years ago

Read 2 more answers

A researcher selects two samples of equal size and computes a mean difference of 1.0 between the two sample means. If the pooled

s344n2d4d5 [400]

Answer:

The Cohen's D is given by this formula:

$D = \frac{\bar X_A -\bar X_B}{s_p}$

Where $s_p$ represent the deviation pooled and we know from the problem that:

$s^2_p = 4$ represent the pooled variance

So then the pooled deviation would be:

$s_p = \sqrt{4}= 2$

And the difference of the two samples is $\bar X_a -\bar X_b = 1$ , and replacing we got:

$D = \frac{1}{2}= 0.5$

And since the value for D obtained is 0.5 we can consider this as a medium effect.

Step-by-step explanation:

Previous concepts

Cohen’s D is a an statistical measure in order to analyze effect size for a given condition compared to other. For example can be used if we can check if one method A has a better effect than another method B in a specific situation.

Solution to the problem

The Cohen's D is given by this formula:

$D = \frac{\bar X_A -\bar X_B}{s_p}$

Where $s_p$ represent the deviation pooled and we know from the problem that:

$s^2_p = 4$ represent the pooled variance

So then the pooled deviation would be:

$s_p = \sqrt{4}= 2$

And the difference of the two samples is $\bar X_a -\bar X_b = 1$ , and replacing we got:

$D = \frac{1}{2}= 0.5$

And since the value for D obtained is 0.5 we can consider this as a medium effect.

7 0

3 years ago