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Vitek1552 [10]
3 years ago
8

A bag contains some number of marbles. It is known that 20 of them are red. When 15 marbles are drawn, without replacement, we g

et 6 red. Assuming E(X)=6 red, what is the total number of marbles in the bag?
Mathematics
1 answer:
Llana [10]3 years ago
8 0

Answer:

The total number of marbles in the bag is 50.

Step-by-step explanation:

Here, we have n trials, without replacement. So the hypergeometric distribution is used.

The mean of the hypergeometric distribution is:

E(X) = \frac{n*k}{N}

In which n is the number of items in the sample, k is the number of items in the population that are classified a success and N is the size of the population.

15 marbles are drawn:

This means that n = 15

A bag contains some number of marbles. It is known that 20 of them are red.

This means that k = 20, since a success is drawing a red marble.

Assuming E(X)=6 red, what is the total number of marbles in the bag?

We have to find N when E(X) = 6

So

E(X) = \frac{n*k}{N}

6 = \frac{15*20}{N}

6N = 300

N = \frac{300}{6}

N = 50

The total number of marbles in the bag is 50.

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...............??..?.?.?.?.?.??..??...??..?.??...??..?.?.? a
viktelen [127]

Answer:

Step-by-step explanation:

2+2=4

8 0
3 years ago
Let e be the line through A (-4,5) and B (3. t) that is perpendicular to the line through
grigory [225]

Answer:

Step-by-step explanation:

product of slopes of perpendicular lines=-1

(t-5)/(3+4)×(2-3)/(-4-1)=-1

(t-5)/7×(-1/-5)=-1

(t-5)/35=-1

t-5=-1×35=-35

t=-35+5

t=-30

2.

slopes of parallel lines are equal.

(-2+3)/(t-4)=(-1-4)/(4+2)

1/(t-4)=-5/6

t-4=-6/5

t=4-6/5=(20-6)/5=14/5

3.

x>0,y<0

so P lies in4th quadrant.

except cos and sec all are negative.

so only cos and sec are positive.

8 0
3 years ago
A roulette wheel has the numbers 1 through 36, 0, and 00. A bet on four numbers pays 8 to 1 (that is, if you bet $1 and one of t
Natasha_Volkova [10]

Answer:

Lose $0.05

Step-by-step explanation:

There are 38 possible spots on the roulette wheel (numbers 1 to 36, 0 and 00).

If the player can choose four numbers on single $1 bet, his chances of winning (W) and losing (L) are as follows:

P(W) = \frac{4}{38} \\P(L) = 1-P(W) = 1-\frac{4}{38} \\P(L) = \frac{34}{38}

The expected value of the bet is given by the probability of winning multiplied by the payout ($8), minus the probability of losing multiplied by the bet cost ($1)

EV=\frac{4}{38}*\$8 -\frac{34}{38}*\$1\\EV= -\$0.05

On each bet, the player is expected to lose 5 cents ($0.05).

4 0
3 years ago
You and two friends visit a pizza shop. There are 15 toppings. 5 toppings are meat and the rest are vegetable. Each of you order
andrew-mc [135]
We know that
total toppings=15
<span>meat toppings=5
</span>
<span>The first person has a
5/15 chance of getting a meat topping.

The second person has a
4/14 chance because there are no repeats,

The third person would have a
3/13 chance.
Since there are three multiply
5/15 * 4/14 * 3/13.=60/2730
</span>60/2730-------> divide by 30 both members------> 2/91

the answer is
2/91
8 0
3 years ago
Translate into an algebraic expressions: b is decreased by 40% and decreased again by 40% . What is the result ?
Vikki [24]

Answer:

b-4/5b

Step-by-step explanation:

b is decreased by 80%

dat is 80/100×b

= b-80/100b

b-4/5b

5 0
3 years ago
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