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Vitek1552 [10]
2 years ago
8

A bag contains some number of marbles. It is known that 20 of them are red. When 15 marbles are drawn, without replacement, we g

et 6 red. Assuming E(X)=6 red, what is the total number of marbles in the bag?
Mathematics
1 answer:
Llana [10]2 years ago
8 0

Answer:

The total number of marbles in the bag is 50.

Step-by-step explanation:

Here, we have n trials, without replacement. So the hypergeometric distribution is used.

The mean of the hypergeometric distribution is:

E(X) = \frac{n*k}{N}

In which n is the number of items in the sample, k is the number of items in the population that are classified a success and N is the size of the population.

15 marbles are drawn:

This means that n = 15

A bag contains some number of marbles. It is known that 20 of them are red.

This means that k = 20, since a success is drawing a red marble.

Assuming E(X)=6 red, what is the total number of marbles in the bag?

We have to find N when E(X) = 6

So

E(X) = \frac{n*k}{N}

6 = \frac{15*20}{N}

6N = 300

N = \frac{300}{6}

N = 50

The total number of marbles in the bag is 50.

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Answer:

They meet in 2.22 hours.

Step-by-step explanation:

We can find the time at which Reagan and Nathan meet by equaling the time as follows:

v_{R} = \frac{x_{R}}{t}  

x_{R} = v_{R}t    (1)      

v_{N} = \frac{x_{N}}{t}  

x_{N} = v_{N}t   (2)

Where R is for Reagan and N for Nathan.

Knowing that:

x_{R} + x_{N} = 40 mi

By adding equations (1) and (2) we have:

x_{R} + x_{N} = v_{R}t + v_{N}t

t = \frac{x_{R} + x_{N}}{|v_{R}| + |v_{N}|} = \frac{40 mi}{8 mi/h + 10 mi/h} = 2.22 h

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Answer:

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Step-by-step explanation:

The probability that a sample mean is 12 or larger for a sample from the horse population is:

Given,

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x, mean age = 10 years.

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To calculate for the probability, we are going to use the formula of normal distribution.

normal distribution is calculated by:

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σ is the standard deviation of the distribution.

The z-value corresponding to 12year is

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we will use the table of normal distribution to find the corresponding z value.

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Thus, the probability of the sample mean is 0.4013, for 60 horses, it is likely that 60 * 0.4013 =24.08 = 24 horses will have 12year or larger.

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