For answer #3...
just replace (T) with 76.50 in the equation T=9h
Then since this is a division problem you would do 76.50/9=9h/9
This gives you your answer which is h=8.5.
Hope this helps!!:)
It seems to be none of the above
Answer:
C. 3.33 hours
Step-by-step explanation:
Use the algebra work equation:
=
+
, where tb is the time to work together, t1 is the time it takes one person, and t2 is the time it takes the other person
Plug in the values we know:
=
+ 
=
+ 
= 
20 = 6tb
3.33 = tb
So, it would take them 3.33 hours when working together.
Answer:
a) see the plots below
b) f(x) is exponential; g(x) is linear (see below for explanation)
c) the function values are never equal
Step-by-step explanation:
a) a graph of the two function values is attached
__
b) Adjacent values of f(x) have a common ratio of 3, so f(x) is exponential (with a base of 3). Adjacent values of g(x) have a common difference of 2, so g(x) is linear (with a slope of 2).
__
c) At x ≥ 1, the slope of f(x) is greater than the slope of g(x), and the value of f(x) is greater than the value of g(x), so the curves can never cross for x > 1. Similarly, for x ≤ 0, the slope of f(x) is less than the slope of g(x). Once again, f(0) is greater than g(0), so the curves can never cross.
In the region between x=0 and x=1, f(x) remains greater than g(x). The smallest difference is about 0.73, near x = 0.545, where the slopes of the two functions are equal.
Answer:
![\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
Step-by-step explanation:
We can simplify the expression under the root first.
Remember to use 
Thus, we have:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D%20%5C%5C%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D)
We know 4th root can be written as "to the power 1/4th". Then we can use the property 
<em>So we have:</em>
<em>
</em>
<em />
<em>Option D is right.</em>