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givi [52]
2 years ago
9

In 2005, there were 12,000 students at Beachon High. In 2010, there were 12,250. What is the rate of change un the number of stu

dents
Mathematics
2 answers:
Troyanec [42]2 years ago
5 0
The rate of change of the number of students was 50
IceJOKER [234]2 years ago
3 0

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

so in this case we have the provided ones (2005 , 12000) and (2010 , 12250)

(\stackrel{x_1}{2005}~,~\stackrel{y_1}{12000})\qquad (\stackrel{x_2}{2010}~,~\stackrel{y_2}{12250}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{12250}-\stackrel{y1}{12000}}}{\underset{run} {\underset{x_2}{2010}-\underset{x_1}{2005}}} \implies \cfrac{12250 -12000}{2010 -2005}\implies \cfrac{250}{5}\implies \underset{\textit{rate of change}}{50}

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Find the central angle of a sector of a circle of the area of the sector and the area of the circle are in the proportion of 3:5
abruzzese [7]

Answer:

\theta = 216

Step-by-step explanation:

Given

Area of Sector : Area of Circle = 3 : 5

Required

Determine the central angle

The question implies that

\frac{Area_{sector}}{Area_{circle}} = \frac{3}{5}

Multiply both sides by 5

5 * \frac{Area_{sector}}{Area_{circle}} = \frac{3}{5} * 5

5 * \frac{Area_{sector}}{Area_{circle}} = 3

Multiply both sides by Area{circle}

5 * \frac{Area_{sector}}{Area_{circle}} * Area_{circle} = 3 * Area_{circle}

5 * {Area_{sector} = 3 * Area_{circle}

Substitute the areas of sector and circle with their respective formulas;

Area_{sector} =\frac{\theta}{360} * \pi r^2

Area_{circle} = \pi r^2

So, we have

5 * \frac{\theta}{360} * \pi r^2 = 3 * \pi r^2

Divide both sides by \pi r^2

5 * \frac{\theta}{360} * \frac{ \pi r^2}{\pi r^2} = 3 * \frac{\pi r^2}{\pi r^2}

5 * \frac{\theta}{360} = 3

Multiply both sides by 360

360 * 5 * \frac{\theta}{360} = 3 * 360

5 * \theta = 3 * 360

Divide both sides by 5

\frac{5 * \theta}{5} = \frac{3 * 360}{5}

\theta = \frac{3 * 360}{5}

\theta = \frac{1080}{5}

\theta = 216

Hence, the central angle is 216 degrees

3 0
2 years ago
For the following pair of variables, state the units that might be used to measure each variable. Then state whether you believe
AfilCa [17]

Answer:

The correct answer is:

There is a positive correlation because women's weight tend to increase when height increases (D)

Step-by-step explanation:

The units that might be used to measure each variable are:

Height : meter (m) or foot (plural, feet) (Ft.)

weight : kilograms (kg) or Pounds (lb)

A positive correlation is said to occur between two variables when they both move in the same direction, that is, when they both increase or decrease, while a negative correlation occurs when the movement is not in tandem, i.e, as one increases, the other decreases. The relationship between height and weight is a positive correlation because, an increase in height, which is mainly as a result of elongation of bones, leads to an accumulated increase in total body mass, which in turn increases the body weight.

8 0
3 years ago
The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. Which graph represents g(x)?
levacccp [35]
<span>The graph would be translated 5 units right and 1 unit up, giving an upward facing parabola with a vertex at (5, 1).

Explanation:
Since 5 was subtracted from x before it was squared, this means a horizontal translation 5 units. Since it was subtracted, this means it was translated right 5 units.

The 1 added at the end means it was translated 1 unit up as well.

This is in vertex form, y=a(x-h)^2 + k, where (h, k) is the vertex; h corresponds with 5 and k corresponds with 1, so the vertex is at (5, 1).</span>
6 0
3 years ago
Read 2 more answers
PLEASE HELPP!<br> A square has an area of 5.76cm². Find the perimeter of the square
nikdorinn [45]
The ar. of square =X^
=5.76
So,X=√5.76
=2.4
now, perimeter of square =4(X)
=4(2.4)
=9.6
So, the perimeter of the square is 9.6cm..

Thanks!

Hope it helps you..
4 0
3 years ago
What are the coordinates
iris [78.8K]
Wheres the picture? It’s not showing up.
6 0
3 years ago
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