1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svlad2 [7]
1 year ago
8

Charles is 20% heavier than Edith. If Charles weighs 60kg, what is Edith's weight?​

Mathematics
1 answer:
ddd [48]1 year ago
4 0

Charles' weight = Edith's weight + 20% of Edith's weight

We'll use a variable to represent Edith's weight, x.

The decimal form of 20% is 0.2.

60 = x + 0.2x

60 = 1.2x

x = 50

Edith's weight is 50kg.

Hope this helps!

You might be interested in
The table shows the input and output of a function Table(input:3,4,6,11. Output:5,7,11,21) write an equation, in function nation
Anni [7]

f(x) = 2x - 1

To obtain a function we require values of x for x = 3, 4, 5 , 6, .....

The output appears to increase in steps of 2

3 → 5

4 → 7

5 → 9

6 → 11

Looking at the consecutive values of y we should see that these are twice the corresponding value of x subtract 1

f(x) = 2x - 1 ← is a possible function

checking the values for x in the input


f(3) =(2 × 3 ) - 1 = 5

f(4) = (2 × 4 ) - 1 = 7

f(6) = (2 × 6 ) - 1 = 11

f(11) = (2 × 11 ) - 1 = 21




6 0
2 years ago
I asked this earlier and got no answer. Will give brainliest
Virty [35]
The area of a square is

s • s

We can also write this as

s^2

So, for any side length “s”, we can make a function, A(s), such that

A(s) = s^2

Now that we have a quadratic equation for the area of a square, let’s go ahead and solve for the side lengths of a square with a given area. In this case, 225 in^2

225 = s^2

Therefore,

s = sqrt(225)

s = 15

So, the dimensions are 15 x 15 in

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=55%20%5Cfrac%7B6%7D%7B9%3F%7D%20%20%5Ctimes%2066%20%5Cfrac%7B5%7D%7B6%7D%20" id="TexFormula1"
JulsSmile [24]

Answer:

Step-by-step explanation:

If you can present a problem in Latex, you can do anything. I don't know what the question mark is for. I'm just ignoring it.

55 2/3 * 66 5/6

One of the ways to get the answer is to use decimals

55.666666667 * 66.833333333 = 3720.38889

Another way to do this problem is to break up one of the numbers

55 2/3 (66 + 5/6)   You can do this if you know how to use the distributive property.

55 2/3 * 66 + 55 2/3 * 5/6

( (165 + 2) / 3) * 66 + (165 + 2)/3 * 5/6

167/3 * 66 + 167 / 3 * 5/6

167 * 22 + (167 * 5 / (3 * 6)

3674 + 835 / 18

3674 + 46 7/18

3720 7/18

If none of these seem right and you have choices, please list them.  

6 0
3 years ago
1 .what is the value of x?<br> 2 .what is the value of y ?
kifflom [539]

Answer:

ans of y is 3 because 12-3=9

8 0
2 years ago
Help me please this will help my grade !
Sauron [17]

Answer: A (I think)

Step-by-step explanation: it would be left of 9 since it’s 8.77496438739

81 square rooted is 9 so 77 square rooted is less than 81 square rooted

And a number line counts up the more you go right.

5 0
2 years ago
Other questions:
  • Given that (4,4) is on the graph of f(x), Find The Corresponding Point for the function f(x)+5
    6·2 answers
  • How much will a person pay for 7.5 pounds of bananas at a price of $2.07 per pound?
    5·1 answer
  • What is the inverse of f(x)=2x−3
    14·1 answer
  • Suppose that both the radius r and height h of a circular cone are increasing at a rate of 7 cm/s. How fast is the volume of the
    8·1 answer
  • 7236 by 25 7236 divided by 25
    6·2 answers
  • HELP ME WITH THIS QUESTION PLZ!!
    12·2 answers
  • Please help me with this question!!
    5·2 answers
  • 1/3 + 1/9 need help fast help
    6·2 answers
  • Joe is painting his wooden fenceposts before putting them in his yard. They are each 8 feet tall and have a diameter of 1 foot.
    11·1 answer
  • Briefly explain how multiple regression enhances the two primary purposes of regression analysis.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!