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Lina20 [59]
3 years ago
10

Find the volume of the square pyramid. A) 64 cm3 B) 96 cm3 C) 144 cm3 D) 288 cm3

Mathematics
2 answers:
marysya [2.9K]3 years ago
6 0

Answer:The answer is b i just did this ...

Step-by-step explanation:

artcher [175]3 years ago
6 0

Answer:

B is correct

Step-by-step explanation:

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25−2(5+4x)
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Step-by-step explanation:

25 - 2(5 + 4x)

= 25 - 10 - 8x (Distributive Property)

= 15 - 8x.

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Which number is in the solution set of the inequality -5x - 7 > 28?
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x>-7

Step-by-step explanation:

A

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What is the slope of (1, -3/4) and (4, -3)
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1-5

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3 years ago
10+4x =12+3x<br><br> How is this solved?
soldier1979 [14.2K]

Answer:

x=2

Step-by-step explanation:

  1. 10+4x=12+3x
  2. 10+4x-3x=12+3x-3x
  3. 10+x=12
  4. 10+x-10=12-10
  5. x=2

<u><em>FINAL ANSWER</em></u>

<em>x=2</em>

8 0
3 years ago
Read 2 more answers
What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S
Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is y=\frac{1}{3} x+2

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3  

And as the line passing through (-3,1) and is  perpendicular to 3x + y = -8, product of slopes of two line will be -1  as lies are perpendicular.

Let required slope = x  

\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}

So we need to find the equation of a line whose slope is \frac{1}{3} and passing through (-3,1)

Equation of line passing through (x_1 , y_1) and having lope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}

Substituting the values we get,

\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}

Hence the required equation of line is found using slope intercept form

4 0
3 years ago
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