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2 years ago

Suppose you know that ∠S and ∠Y are complementary, and that m∠S = 2(m∠Y) − 75°. Find m∠Y.

Mathematics

1 answer:

umka2103 [35]2 years ago

3 0

m∠s + m∠y = 90

m∠s = 90 - m∠y

m∠s= 2(m∠y) - 75

90 - m∠y = 2 m∠y -75

90 + 75 = 3 (m∠y)

165 = 3 (m∠y)

55= m∠y

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PLEASE HELP ME !!!!!!!!!!

jasenka [17]

Answer:

The load weight is 2.29 N

Step-by-step explanation:

We note that at equilibrium, the sum of the moment and the sum of forces about a point is zero, therefore, we have;

∑M =0

∑F = 0

The parameters given are;

The distance of the load from the hinge = 35 cm

The distance of the load from the spring balance = 15 cm

The applied force on the spring balance = 4 N↑

The direction of the applied force on the spring balance = Upwards

Let the weight of the load = W↓

The direction of the weight of the load = Downwards

We use downward negative and upward positive coefficients for the forces

We take moment about the hinge as follows;

Sum of moments equals zero gives;

4 × (35 - 15) - W × 35 = 0

∴ 4 × (35 - 15) = W × 35

4 × 20 = W × 35

W = 4 × 20/35 = 2.29 N

The weight of the load = 2.29 N.

5 0

3 years ago

Misty owes the bank $32. She gets $45 for her birthday and deposits it into her account. How much does she

tatuchka [14]

Answer:

she has 13 dollars left

Step-by-step explanation:

simple math of subtraction. 45 - 32 = 13

13 goes into her account after paying her debt to the bank

8 0

2 years ago

Peter decides to invest $1,200,000 in a period annuity that earns 4.6% APR compounded monthly for a period of 20 years. How much

ad-work [718]

Given is the Present Value of annuity, PV = 1,200,000 dollars.

Given that 4.6% APR compounded monthly i.e. r = 4.6%/12 = 0.003833

Given that 20 years of investment i.e. N = 20x12 = 240

It says to find monthly income from the annuity.

We know the formula for Periodic Payment (when PV is known) is given as follows :-

$Periodic \;payment = \frac{PV}{\frac{1-\frac{1}{(1+r)^{N}}}{r}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{1-\frac{1}{(1+0.003833)^{240}}}{0.003833}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{1-\frac{1}{(1.003833)^{240}}}{0.003833}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{1-\frac{1}{2.504681211}}{0.003833}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{1-0.399252406}{0.003833}} \\\\Periodic \;payment = \frac{1,200,000}{\frac{0.600747594}{0.003833}}$