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mixer [17]
2 years ago
13

Suppose you know that ∠S and ∠Y are complementary, and that m∠S = 2(m∠Y) − 75°. Find m∠Y.

Mathematics
1 answer:
umka2103 [35]2 years ago
3 0

m∠s + m∠y = 90

m∠s = 90 - m∠y            

m∠s= 2(m∠y) - 75

90 - m∠y = 2 m∠y -75

90 + 75 = 3 (m∠y)

165 = 3 (m∠y)

55= m∠y

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Answer:

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Step-by-step explanation:

=> \sf 3.64+\frac{3}{5}                    [\sf \frac{3}{5} = 0.6]

=> 3.64 + 0.6

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2 years ago
What is the equivalent expression for 2x + 8y​
klio [65]

If this helps you consider making it brainliest as it helps me out.

2(x+4y) is the equivalent expression.

Let’s say x = 1 and y = 2

Then 2x + 8y would be 18

Same thing for 2(x+4y)

Hope this helps!

7 0
3 years ago
Read 2 more answers
Trevon’s school is selling tickets to a fall musical. On the first day of ticket sales the school sold 13 adult tickets and 12 s
julsineya [31]

9514 1404 393

Answer:

  • adult: $7
  • student: $10

Step-by-step explanation:

Let a and s represent the prices of adult and student tickets, respectively.

  13a +12s = 211 . . . . . . ticket sales the first day

  5a +3s = 65 . . . . . . . ticket sales the second day

Subtracting the first equation from 4 times the second gives ...

  4(5a +3s) -(13a +12s) = 4(65) -(211)

  7a = 49 . . . . . . . simplify

  a = 7 . . . . . . . divide by 7

  5(7) +3s = 65 . . . . substitute into the second equation

  3s = 30 . . . . . . . subtract 35

  s = 10 . . . . . . . divide by 3

The price of one adult ticket is $7; the price of one student ticket is $10.

7 0
3 years ago
Solve using the elimination method:<br> X-3y=7<br> 3x + 3y=9
sergij07 [2.7K]

Answer:

                        x=4\\\\y=-1

Step-by-step explanation:

Given Equation:

x-3y=7      Equation:1

3x + 3y=9     Equation:2

Dividing Equation:2 by '3' both the sides:

x+y=3      

or   x=3-y     Equation:3

Putting the vale of 'x' in Equation:1

                             x-3y=7

                          (3-y)-3y=7\\\\3-y-3y=7\\\\3-4y=7\\\\

Subtracting '3' both sides

                             -4y=7-3\\\\-4y=4

                                 y=\frac{4}{-4}

                                 y=-1

Putting value of 'y' in Equation:3

                                x=3-y

                                x=3-(-1)\\\\x=3+1\\\\x=4

The solution of the equations is :

                              x=4\\\\y=-1

7 0
3 years ago
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