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Lesechka [4]
2 years ago
12

When graphing f(x)=a sin(bx) you would determine the functions period using which of the following?

Mathematics
1 answer:
juin [17]2 years ago
6 0
<h3>Answer:  A. The period is 2pi/b</h3>

Explanation:

The value of 'a' out front in y = a sin(bx) determines the amplitude.

The b term helps us compute the period, which is 2pi/b for sine, cosine, secant, and cosecant functions.

For example, y = 2sin(3x) has an amplitude of 2 and period of 2pi/3

For tangent and cotangent functions, the period would be pi/b.

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<h3>Hello There!!</h3>

<u>Given</u>

Perimeter = (32x + 8)

<u>To </u><u>Find</u>

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<u>We Know,</u>

\text{Perimeter of Square = 4 × sides}

\text{ 32x + 8} = 4 \times  \text{sides} \\  \\   \fbox{dividing each side with 4} \\  \\  \implies  \text{( 32x} \div 4) + (8 \div 4) =  \frac{4 \times  \text{sides}} {4} \\  \\ \implies  \text{8x + 2} =  \frac{ \cancel4 \times  \text{sides}} { \cancel4}   \\  \\  \implies  \text{sides} = \text{8x + 2}

\therefore \text{ Length of the Patio} =  \text \red{ \underline{8x + 2 feet}}

<h3>Hope this helps!!</h3>
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