Reduce the fraction into simplest terms. 9/12

Mathematics

2 answers:

solong [7]3 years ago

8 0

Answer:

3/4

Step-by-step explanation:

divided by 3 to get the answer.

kolezko [41]3 years ago

5 0

Answer:

$\frac{3}{4}$

Step-by-step explanation:

9 can also be written as 3×3 & 12 can also be written as 3×4.

So if we gonna cancel out a 3 from 9 & 12 , then the remaining numbers in 9 & 12 will be 3 & 4.

$\frac{9}{12}=\frac{3*3}{3*4} = \frac{3}{4}$

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4. Tell whether the systems have one solution,

hjlf

Answer:

x= 2,

,y = 5

Step-by-step explanation:

Solve by Substitution :

// Solve equation [1] for the variable y

[1] y = 5x - 5

// Plug this in for variable y in equation [2]

[2] -4x + 2•(5x-5) = 2

[2] 6x = 12

// Solve equation [2] for the variable x

[2] 6x = 12

[2] x = 2

// By now we know this much :

x = 2

y = 5x-5

// Use the x value to solve for y

y = 5(2)-5 = 5

Solution :

{x,y} = {2,5}

5 0

2 years ago

According to a poll, 83% of California adults (418 out of 506 surveyed) feel that education is one of the top issues facing Cali

SpyIntel [72]

Answer:

A point estimate for the true population proportion is $\hat{p} = 0.83$ and the 90% confidence interval is (0.8025, 0.8575)

Step-by-step explanation:

We have a large sample of people of size n = 506. Let X be the random variable that represents the number of adults who feel that education is one of the top issues facing California. We are interested in the unknown true proportion p of adults who feel that education is one of the top issues facing California. A point estimate for the true population proportion is given by $\hat{p}$ = X/n = 418/506 = 0.83, the standard deviation is given by $\sigma_{\hat{p}} = \sqrt{p(1-p)/n}\approx\sqrt{\hat{p}(1-\hat{p})/n} = \sqrt{(0.83)(0.17)/506} = 0.0167$ . Therefore, the 90% confidence interval for the true population proportion is $\hat{p}\pm z_{0.1/2}\sqrt{\hat{p}(1-\hat{p})/n}$ , i.e., $0.83\pm z_{0.05}0.0167$ , i.e., $0.83\pm (1.6448)(0.0167)$ , (0.8025, 0.8575).