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Anton [14]
2 years ago
7

Square root of 3x+ 4 = 5.

Mathematics
1 answer:
Arturiano [62]2 years ago
7 0

Answer:

x=7

Step-by-step explanation:

5^2=25\\3*7=21+4=25\\\sqrt{25}=5

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T(x)=1-2x how do you graph this problem
Eva8 [605]

Answer:

Explained

Step-by-step explanation:

The 1 is the y-intercept

The -2 is the slope

First place a point at (0,1)

Then, because it's negative from left to right the graph is decreasing (going lower on the y-axis the farther you go on the x-axis).

Slope is rise over run so the -2 affects how far it goes. So for each value of x that increases by one, a new point will be two units down and one unit right of the previous point. To graph to the left of the y-intercept then you do that backwards where the next point is two units up and one unit left.


Then just draw a straight line connecting all the points.

7 0
3 years ago
Find the slope of a line parallel to the line through the given points. P(-2, 4), Q(6, -2) 4/3 3/4 -3/4
Galina-37 [17]

Answer:

slope = - \frac{3}{4}

Step-by-step explanation:

Parallel lines have equal slopes thus the slope of a parallel line will be equal to the slope of PQ

To calculate slope m use the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = P(- 2, 4) and (x₂, y₂ ) = Q(6, - 2)

m = \frac{-2-4}{6+2} = \frac{-6}{8} = - \frac{3}{4}

8 0
3 years ago
Read 2 more answers
Can you divide an odd number into two equal groups
Maslowich

Answer:

No you can not it would come out as a decimal form.

Step-by-step explanation:

3 divided by 2 is 1.5 or 1 1/2

This is not divided evenly between each other

This proves that (no) anything that is a odd number can not be divided equally

Hope that helps

7 0
2 years ago
HELP ON A TEST
Strike441 [17]
First three. A, b, c.
The triangle is a right triangle.
The triangle is a Pythagorean triple.
The triangles hypotenuse is 39 inches.
7 0
3 years ago
Pls help me!!
vlada-n [284]

Answer:

<h3>Q1</h3>

The graph of y = f(x), has vertex at (1, -2)

<u>The vertex of a function f(x - 3) is going to be:</u>

  • (1 - 3, -2) = (-2, -2)
<h3>Q2</h3>
  • <em>The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another point that must lie on the graph of y = f(x).</em>

The axis of symmetry is at the same distance from the symmetric points.

x = 5 is a vertical line. The point (8, -7) is 3 units to the right. So the mirror point will be 3 units to the left and have same y-coordinate: x = 5 - 3 = 2

The point is (2, -7)

<h3>Q3</h3>

The graph in blue is the translation of the red to the left by 2 units.

<u>So the equation is:</u>

  • y = f(x + 2)
<h3>Q4</h3>

y = h(x) is graphed

  • h(7) = 5
  • h(h(7)) = h(5) = -1
<h3>Q5</h3>

The graph of the function y = u(x) given

This is a odd function.

The coordinates of u(x) and u(-x) add to zero because u(-x) = -u(x)

<u>Therefore:</u>

  • u(-2.72) + u(-0.81) + u(0.81) + u(2.72) =
  • [u(-2.72) + u(2.72)] + [u(-0.81) + u(0.81)] =
  • 0 + 0 = 0
3 0
3 years ago
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